我找到了一个关于如何从Android中的HTTPPOST调用JSON的示例。现在我可以使用以下链接在我的localhost上调用A服务:(http://10.0.2.2/testingjson/testing.json)
它给出了listView中的输出,这很棒!
现在我需要或要求的是我想在链接上插入一些额外的信息,如
http://10.0.2.2/testingjson/testing.json?regid=1234&pass="abcd"
有两个java文件,Main和JSONfunction。
以下是所有代码:
Main.java:
package com.android.jsontut;
import java.util.ArrayList;
import java.util.HashMap;
import org.json.JSONArray;
import org.json.JSONException;
import org.json.JSONObject;
import org.w3c.dom.Document;
import org.w3c.dom.Element;
import org.w3c.dom.NodeList;
import android.app.ListActivity;
import android.content.Intent;
import android.os.Bundle;
import android.util.Log;
import android.view.View;
import android.widget.AdapterView;
import android.widget.AdapterView.OnItemClickListener;
import android.widget.ListAdapter;
import android.widget.ListView;
import android.widget.SimpleAdapter;
import android.widget.Toast;
public class Main extends ListActivity {
/** Called when the activity is first created. */
@Override
public void onCreate(Bundle savedInstanceState) {
super.onCreate(savedInstanceState);
setContentView(R.layout.listplaceholder);
ArrayList<HashMap<String, String>> mylist = new ArrayList<HashMap<String, String>>();
JSONObject json = JSONfunctions.getJSONfromURL("http://10.0.2.2/testingjson/testing.json");
try{
JSONArray earthquakes = json.getJSONArray("earthquakes");
for(int i=0;i<earthquakes.length();i++){
HashMap<String, String> map = new HashMap<String, String>();
JSONObject e = earthquakes.getJSONObject(i);
map.put("id", String.valueOf(i));
map.put("name", "Earthquake name:" + e.getString("eqid"));
map.put("magnitude", "Magnitude: " + e.getString("magnitude"));
mylist.add(map);
}
}catch(JSONException e) {
Log.e("log_tag", "Error parsing data "+e.toString());
}
ListAdapter adapter = new SimpleAdapter(this, mylist , R.layout.main,
new String[] { "name", "magnitude" },
new int[] { R.id.item_title, R.id.item_subtitle });
setListAdapter(adapter);
final ListView lv = getListView();
lv.setTextFilterEnabled(true);
lv.setOnItemClickListener(new OnItemClickListener() {
public void onItemClick(AdapterView<?> parent, View view, int position, long id) {
@SuppressWarnings("unchecked")
HashMap<String, String> o = (HashMap<String, String>) lv.getItemAtPosition(position);
Toast.makeText(Main.this, "ID '" + o.get("id") + "' was clicked.", Toast.LENGTH_SHORT).show();
}
});
}
}
现在是第二个文件:
JSONFUNCTIONS.java
package com.android.jsontut;
import java.io.BufferedReader;
import java.io.InputStream;
import java.io.InputStreamReader;
import java.util.HashMap;
import org.apache.http.HttpEntity;
import org.apache.http.HttpResponse;
import org.apache.http.client.HttpClient;
import org.apache.http.client.entity.UrlEncodedFormEntity;
import org.apache.http.client.methods.HttpPost;
import org.apache.http.impl.client.DefaultHttpClient;
import org.json.JSONArray;
import org.json.JSONException;
import org.json.JSONObject;
import android.util.Log;
public class JSONfunctions {
public static JSONObject getJSONfromURL(String url){
InputStream is = null;
String result = "";
JSONObject jArray = null;
//http post
try{
HttpClient httpclient = new DefaultHttpClient();
HttpPost httppost = new HttpPost(url);
HttpResponse response = httpclient.execute(httppost);
HttpEntity entity = response.getEntity();
is = entity.getContent();
}catch(Exception e){
Log.e("log_tag", "Error in http connection "+e.toString());
}
//convert response to string
try{
BufferedReader reader = new BufferedReader(new InputStreamReader(is,"iso-8859-1"),8);
StringBuilder sb = new StringBuilder();
String line = null;
while ((line = reader.readLine()) != null) {
sb.append(line + "\n");
}
is.close();
result=sb.toString();
}catch(Exception e){
Log.e("log_tag", "Error converting result "+e.toString());
}
try{
jArray = new JSONObject(result);
}catch(JSONException e){
Log.e("log_tag", "Error parsing data "+e.toString());
}
return jArray;
}
}
有没有完整的示例,我可以在这里学习如何在此示例中添加Header?或任何天才可以帮助我吗? :)
我愿意解决这个问题,所以我很乐意详细讨论解决这个问题! :)
如果需要更多信息,请告诉我。
提前致谢!
答案 0 :(得分:1)
如果你真的想要使用POST,你需要创建一个NameValuePair对象并用你的参数填充它。
List<NameValuePair> nameValuePairs = new ArrayList<NameValuePair>(2);
nameValuePairs.add(new BasicNameValuePair("regid", "123"));
nameValuePairs.add(new BasicNameValuePair("pass", "abcd"));
httppost.setEntity(new UrlEncodedFormEntity(nameValuePairs));
但我怀疑,因为你只是在获取一个JSON对象,所以你实际上并不想使用HttpPost对象来发出请求。看看HttpGet,它将允许你使用你发布的网址(http://10.0.0.2/some/url?param=123&otherparam=456)。你仍然可以用同样的方式阅读回复。
答案 1 :(得分:1)
我很想知道你是想把它放在查询字符串上还是在标题中。查询字符串变量将在URL的末尾(例如http://10.0.2.2/testingjson/testing.json?regid=1234&pass=“abcd”)
至于标题看起来HttpPost类有一个继承的 addHeader() 方法。
所以它会像:
HttpClient httpclient = new DefaultHttpClient();
HttpPost httppost = new HttpPost(url);
httpPost.addHeader(new BasicHeader("regid", "1234"));