从我在Stack Exchange和其他地方看到的所有内容中,我已经正确设置了所有内容,以便在Android OS启动时启动IntentService。不幸的是它没有启动,我没有收到任何错误。也许专家可以提供帮助...
清单:
<?xml version="1.0" encoding="utf-8"?>
<manifest xmlns:android="http://schemas.android.com/apk/res/android"
package="com.phx.batterylogger"
android:versionCode="1"
android:versionName="1.0"
android:installLocation="internalOnly">
<uses-sdk android:minSdkVersion="8" />
<uses-permission android:name="android.permission.RECEIVE_BOOT_COMPLETED" />
<uses-permission android:name="android.permission.WRITE_EXTERNAL_STORAGE" />
<uses-permission android:name="android.permission.BATTERY_STATS" />
<application android:icon="@drawable/icon" android:label="@string/app_name">
<service android:name=".BatteryLogger"/>
<receiver android:name=".StartupIntentReceiver">
<intent-filter>
<action android:name="android.intent.action.BOOT_COMPLETED" />
</intent-filter>
</receiver>
</application>
</manifest>
BroadcastReceiver for Startup:
package com.phx.batterylogger;
import android.content.BroadcastReceiver;
import android.content.Context;
import android.content.Intent;
public class StartupIntentReceiver extends BroadcastReceiver {
@Override
public void onReceive(Context context, Intent intent) {
Intent serviceIntent = new Intent(context, BatteryLogger.class);
context.startService(serviceIntent);
}
}
更新:我尝试了下面的所有建议,并将Log.v("BatteryLogger", "Got to onReceive, about to start service");
等日志记录添加到StartupIntentReceiver的onReceive处理程序中,并且没有记录任何内容。所以它甚至没有进入BroadcastReceiver。
我认为我正在部署APK并正确测试,只需在Eclipse中运行Debug,控制台说它已成功将其安装到我的Xoom平板电脑\ BatteryLogger \ bin \ BatteryLogger.apk。然后进行测试,我重新启动平板电脑,然后查看DDMS中的日志,并在操作系统设置中检查正在运行的服务。这听起来是否正确,或者我错过了什么?再次,非常感谢任何帮助。
答案 0 :(得分:265)
这里有一个AutoStart应用程序的完整示例
AndroidManifest文件
<?xml version="1.0" encoding="utf-8"?>
<manifest xmlns:android="http://schemas.android.com/apk/res/android"
package="pack.saltriver" android:versionCode="1" android:versionName="1.0">
<uses-permission android:name="android.permission.RECEIVE_BOOT_COMPLETED" />
<application android:icon="@drawable/icon" android:label="@string/app_name">
<receiver android:name=".autostart">
<intent-filter>
<action android:name="android.intent.action.BOOT_COMPLETED" />
</intent-filter>
</receiver>
<activity android:name=".hello"></activity>
<service android:enabled="true" android:name=".service" />
</application>
</manifest>
<强> autostart.java 强>
public class autostart extends BroadcastReceiver
{
public void onReceive(Context context, Intent arg1)
{
Intent intent = new Intent(context,service.class);
if (Build.VERSION.SDK_INT >= Build.VERSION_CODES.O) {
context.startForegroundService(intent);
} else {
context.startService(intent);
}
Log.i("Autostart", "started");
}
}
<强> service.java 强>
public class service extends Service
{
private static final String TAG = "MyService";
@Override
public IBinder onBind(Intent intent) {
return null;
}
public void onDestroy() {
Toast.makeText(this, "My Service Stopped", Toast.LENGTH_LONG).show();
Log.d(TAG, "onDestroy");
}
@Override
public void onStart(Intent intent, int startid)
{
Intent intents = new Intent(getBaseContext(),hello.class);
intents.setFlags(Intent.FLAG_ACTIVITY_NEW_TASK);
startActivity(intents);
Toast.makeText(this, "My Service Started", Toast.LENGTH_LONG).show();
Log.d(TAG, "onStart");
}
}
hello.java - 执行Applicaton一次后,每次启动设备时都会弹出。
public class hello extends Activity
{
public void onCreate(Bundle savedInstanceState)
{
super.onCreate(savedInstanceState);
setContentView(R.layout.main);
Toast.makeText(getBaseContext(), "Hello........", Toast.LENGTH_LONG).show();
}
}
答案 1 :(得分:2)
以下应该工作。我已经验证了。可能是你的问题在别的地方。
public class MyReceiver extends BroadcastReceiver{
@Override
public void onReceive(Context context, Intent intent) {
Log.d("TAG", "MyReceiver");
Intent serviceIntent = new Intent(context, Test1Service.class);
context.startService(serviceIntent);
}
}
public class Test1Service extends Service {
/** Called when the activity is first created. */
@Override
public void onCreate() {
super.onCreate();
Log.d("TAG", "Service created.");
}
@Override
public int onStartCommand(Intent intent, int flags, int startId) {
Log.d("TAG", "Service started.");
return super.onStartCommand(intent, flags, startId);
}
@Override
public void onStart(Intent intent, int startId) {
super.onStart(intent, startId);
Log.d("TAG", "Service started.");
}
@Override
public IBinder onBind(Intent arg0) {
return null;
}
}
<?xml version="1.0" encoding="utf-8"?>
<manifest xmlns:android="http://schemas.android.com/apk/res/android"
package="com.test"
android:versionCode="1"
android:versionName="1.0"
android:installLocation="internalOnly">
<uses-sdk android:minSdkVersion="8" />
<application android:icon="@drawable/icon" android:label="@string/app_name">
<uses-permission android:name="android.permission.RECEIVE_BOOT_COMPLETED" />
<uses-permission android:name="android.permission.WRITE_EXTERNAL_STORAGE" />
<uses-permission android:name="android.permission.BATTERY_STATS"
/>
<!-- <activity android:name=".MyActivity">
<intent-filter>
<action android:name="android.intent.action.MAIN" />
<category android:name="android.intent.category.LAUNCHER"></category>
</intent-filter>
</activity> -->
<service android:name=".Test1Service"
android:label="@string/app_name"
>
</service>
<receiver android:name=".MyReceiver">
<intent-filter>
<action android:name="android.intent.action.BOOT_COMPLETED" />
</intent-filter>
</receiver>
</application>
</manifest>
答案 2 :(得分:2)
由于设备在启动后进入休眠状态,您的服务可能会在完成之前关闭。您需要先获得唤醒锁定。幸运的是,Support library gives us a class要做到这一点:
public class SimpleWakefulReceiver extends WakefulBroadcastReceiver {
@Override
public void onReceive(Context context, Intent intent) {
// This is the Intent to deliver to our service.
Intent service = new Intent(context, SimpleWakefulService.class);
// Start the service, keeping the device awake while it is launching.
Log.i("SimpleWakefulReceiver", "Starting service @ " + SystemClock.elapsedRealtime());
startWakefulService(context, service);
}
}
然后,在您的服务中,确保释放唤醒锁:
@Override
protected void onHandleIntent(Intent intent) {
// At this point SimpleWakefulReceiver is still holding a wake lock
// for us. We can do whatever we need to here and then tell it that
// it can release the wakelock.
...
Log.i("SimpleWakefulReceiver", "Completed service @ " + SystemClock.elapsedRealtime());
SimpleWakefulReceiver.completeWakefulIntent(intent);
}
不要忘记添加WAKE_LOCK权限:
<uses-permission android:name="android.permission.RECEIVE_BOOT_COMPLETED" />
<uses-permission android:name="android.permission.WAKE_LOCK" />
答案 3 :(得分:1)
看起来与mine非常相似,但我使用接收器的完整包名称:
<receiver android:name=".StartupIntentReceiver">
我有:
<receiver android:name="com.your.package.AutoStart">
答案 4 :(得分:1)
我没有完整的包就取得了成功,你知道调用链在哪里被打断了吗?如果您使用Log()
调试,它在什么时候不再有效?
我认为它可能在您的IntentService中,这看起来很好。
答案 5 :(得分:1)
我找到了一种方法,可以在设备重启时使您的应用正常运行,请按照以下步骤操作。
AndroidManifest文件
<?xml version="1.0" encoding="utf-8"?>
<manifest xmlns:android="http://schemas.android.com/apk/res/android"
package="pack.saltriver" android:versionCode="1" android:versionName="1.0">
<uses-permission
android:name="android.permission.REQUEST_IGNORE_BATTERY_OPTIMIZATIONS"/>
<uses-permission android:name="android.permission.RECEIVE_BOOT_COMPLETED" />
<application android:icon="@drawable/icon" android:label="@string/app_name">
<activity android:name=".MainActivity">
<intent-filter>
<action android:name="android.intent.action.MAIN" />
<category android:name="android.intent.category.LAUNCHER" />
</intent-filter>
</activity>
<receiver android:name=".UIBootReceiver" android:enabled="true"
android:exported="true">
<intent-filter>
<action android:name="android.intent.action.BOOT_COMPLETED" />
<category android:name="android.intent.category.DEFAULT" />
</intent-filter>
</receiver>
<service android:name=".class_Service" />
</application>
UIBootReceiver
public class UIBootReceiver extends BroadcastReceiver {
private static final String TAG = "UIBootReceiver";
@Override
public void onReceive(Context context, Intent arg1)
{
Toast.makeText(context, "started", Toast.LENGTH_SHORT).show();
Intent intent = new Intent(context,class_Service.class);
context.startService(intent);
}
}
这是请求权限,无需管理此应用程序的电池节省,因此您可以稳定地在后台运行。
在MainActivity类的onCreate()中声明以下代码:
Intent myIntent = new Intent();
if (Build.VERSION.SDK_INT >= Build.VERSION_CODES.M) {
myIntent.setAction(Settings.ACTION_REQUEST_IGNORE_BATTERY_OPTIMIZATIONS);
myIntent.setData(Uri.parse("package:" +
DeviceMovingSpeed.this.getPackageName()));
}
startActivity(myIntent);
答案 6 :(得分:0)
就像注释中提到的那样,只是为了简化搜索,所以从3.1开始是不可能的 https://stackoverflow.com/a/19856367/6505257