Question

如何从每行删除三个以上的空格并在那里结束字符串以使用c＃查看右边的行？

[Example1]  
PO BOX XXX                                       OVERDUE - PAY NOW  
then transform to  
PO BOX XXX

[Example2]  
ClientB                                AMOUNT CARRI  
then transform to  
ClientB  

[Example3]  
PO BOX 400                                                    FORWARD TO N  
then transform to  
PO BOX 400

Answer 1

var firstColumn = origString.SubString(0, origString.IndexOf("   "));

Answer 2

input = "PO BOX XXX                                       OVERDUE - PAY NOW  ";
input = input.Remove(input.IndexOf("   "));

indexOf paranthesis中有3个空格

如果您不知道是否有标签或空格，您可以进行拆分 -

input = input.Split(new char[] {' ', '\t'}, StringSplitOptions.RemoveEmptyEntries)[0];

Answer 3

你可以这样做：

var input = new string[3] { "PO BOX XXX                                       OVERDUE - PAY NOW  ", 
                                      "ClientB                                AMOUNT CARRI",
                                      "PO BOX 400                                                    FORWARD TO N  "
                                    };

    for (int x = 0, len = input.Length; x != len; x++)
    {
         input[x] = Regex.Replace(input[x], @"\s{3}[^\n]+", string.Empty);
    }
     //input is ["PO BOX XXX","ClientB","PO BOX 400"]

使用linq：

 var output = input.Select(str => Regex.Replace(str, @"\s{3}[^\r\n]+$", string.Empty));

如果你从文件中读取这个字符串，你可以这样做：

var file = @"D:\file.txt";
var lines = File.ReadAllLines(file);
var output = lines.Select(str => Regex.Replace(str, @"\s{3}[^\n]+$", string.Empty)); // is ["PO BOX XXX","ClientB","PO BOX 400"]

Answer 4

您可以使用string.Split方法生成字符串[]。根据数组计算，您可以获取所需的元素。

string base string = "PO BOX XXX OVERDUE - PAY NOW";
string[] delimittedStringArray = baseString.Split(' ');
if(delimittedStringArray.Length > 3)
{
  // Take the data from array
}
else
{
  // Do what ever
}

//我不确定if条件下是长度还是计数。

字符串操作将字符串截断到C＃上的指定表达式

4 个答案: