Question

我想在php页面上显示不同的消息，基于mysql表行中的值

    if (Select * from subscription_details where student id=session id of student) count = 0

    message: Please sign-up for a subscription package

    else if 

(select * from subscription_details where ((student id = session_id of student) count > 0)  AND ((status=active) count < 1)

    message: Your subscription has expired, please renew subscription

在这些场景中编写SQL需要帮助。

提前致谢，

Answer 1

获取单个查询并读出两个变量：

select
    case when not exists (
        select * from subscription_details sd1
        where sd1.student_id = @session_id
    ) then 1 else 0 end as needsSignup,

    case when not exists (
        select * from subscription_details sd2
        where sd2.student_id = @session_id
        and status = 'active'
    ) then 1 else 0 end as isExpired

演示：http://sqlize.com/n0amP9Uxb5

PHP代码：

// connect to db and run query above
// read first row into $needsSignup and $isExpired.

if ($needsSignup)
{
    // signup code
}
else if ($isExpired)
{
    // expired code
}

Answer 2

$student_id = mysql_real_escape_string($_SESSION['id']);
$query = "SELECT 
            count(*) as NumberOfSubcriptions
            count(s2.id) as NumberActive
          FROM subsciption_details s1
          LEFT JOIN subsciption_details s2 ON (s1.id = s2.id)
          WHERE s1.student_id = '$student_id' 
            AND s2.active = 'active' ";
$result = mysql_query($query);
$row = mysql_fetch_row($result);
if ($row['NumberOfSubcriptions'] >= 1) {.....}
else {}
if ($row['NumberActive'] >= 1) {do stuff with active subscriptions} 
else {....

Answer 3

$pdo = new PDO(...);

$result = $pdo->query("Select status from subscription_details 
                       where student_id=session_id limit 1")->fetch();

if (empty($result)) {
    echo "message: Please sign-up for a subscription package";
} else if ($result['status'] != 'active') {
    echo "message: Your subscription has expired, please renew subscription";
}

Answer 4

也许是这样的？

    $student = mysql_query("Select * from subscription_details where student_id=$session_id;");

    $status = mysql_query("select status from subscription_details where student id = session_id AND status=active");

   if (count(mysql_fetch_row($student)))
          print "message: Please sign-up for a subscription package";

   else if (count(mysql_fetch_row($status)))
          print "message: Your subscription has expired, please renew subscription";

Answer 5

检测注册：

SELECT COUNT(*) AS NumSubscriptions
FROM subscription_details 
WHERE student_id=123;

检测到期时间

SELECT COUNT(*) AS NumActive
FROM subscription_details 
WHERE student id = 123
AND status=inactive;

Answer 6

你能不能按照以下方式做点什么？

$query = mysql_query("SELECT * FROM `subscription_details` WHERE (`student_id` = '$session_id_of_student' AND `status` = 'active')") or die(mysql_error());

$amount = mysql_num_rows($query);

if ($amount == 0) {

    // Do something

} else if ($amount > 0 ) {

    // Do something else

}

检查MYSQL中是否存在行

6 个答案: