Question

我正在尝试使用django-tastypie来设计一个RESTful api。我遇到了一个问题：

# the RevisionObject retrieve commits info through pysvn
# This Resource is fully functionnal (RevisionObject code is not here)
class RevisionResource(Resource):
    id = fields.CharField(attribute='revision')
    description = fields.CharField(attribute='message')
    author = fields.CharField(attribute='author')
    changed_path = fields.ListField(attribute='changed_paths')

    class Meta:
        object_class = RevisionObject
        allowed_methods = ['get']
        resource_name = 'revision'

class RevisionToApplyResource(ModelResource):
    #### here's the problem
    revision = fields.ToManyField(RevisionResource, 'revision')
    ####
    class Meta:
        queryset = RevisionToApply.objects.all()

在我的models.py中，我有：

class RevisionToApply(models.Model):
    patch = models.ForeignKey(PatchRequest)
    revision = models.PositiveIntegerField()
    applied = models.BooleanField(default = False)

我的问题是RevisionToApply模型（对于django）使用int来修改。

如何告诉tastypie使用RevisionToApplyResource的revision字段作为指向RevisionResource的指针？如果ToXxxxField仅用于链接django模型，那么插入ResourceObject的最佳时刻是什么？

感谢。

class NoForeignKeyToOneField(ToOneField):
    def dehydrate(self, bundle):
        try:
            obj_key = getattr(bundle.obj, self.attribute)
            foreign_obj = self.to_class().obj_get(pk=obj_key)
        except ObjectDoesNotExist:
            foreign_obj= None

        if not foreign_obj:
            if not self.null:
                raise ApiFieldError("The model '%r' has an empty attribute"
                   "'%s' and doesn't allow null value." % (bundle.obj,
                   self.attribute))
            return None

        self.fk_resource = self.get_related_resource(foreign_obj)
        fk_bundle = Bundle(obj=foreign_obj, request=bundle.request)
        return self.dehydrate_related(fk_bundle, self.fk_resource)

Answer 1

这是我将如何做到的。看一下ToOneField类是如何工作的，你会注意到水合物/脱水方法对负责获取和设置实际的相关实例。通过继承ToOneField并重写这两种方法，您可以获得Tastypie自动资源处理的好处，而无需实际的外键。

（我指的是ToOneField而不是ToManyField，因为在您的模型中，给定的RevisionToApply只能指向一个修订版。“

它看起来像这样：

class NoForeignKeyToOneField(ToOneField):

    def dehydrate(self, bundle):
        # Look up the related object manually
        try:
            obj_key = getattr(bundle.obj, self.attribute)
            ###
            # Get the revision object here. If you want to make it generic,
            # maybe pass a callable on __init__ that can be invoked here
            ###
            foreign_obj = revision_object
        except ObjectDoesNotExist:
            foreign_obj = None
        # The rest remains the same
        if not foreign_obj:
            if not self.null:
                raise ApiFieldError("The model '%r' has an empty attribute '%s' and doesn't allow a null value." % (bundle.obj, self.attribute))
            return None

        self.fk_resource = self.get_related_resource(foreign_obj)
        fk_bundle = Bundle(obj=foreign_obj, request=bundle.request)
        return self.dehydrate_related(fk_bundle, self.fk_resource)

    def hydrate(self, bundle):
        value = super(NoForeignKeyToOneField, self).hydrate(bundle)

        if value is None:
            return value

        # Here, don't return the full resource, only the primary key
        related_resource = self.build_related_resource(value, request=bundle.request)
        return related_resource.pk

然后在您的资源中使用此字段类型，而不是基本ToOneField。我没有对它进行过测试，但我相信这种方法听起来很简单，而且可以完成工作。

django-tastypie：将ModelResource链接到Resource

1 个答案: