Question

我有两个日期：

开始日期：2010-12-24
截止日期：2011-10-06（今天）

现在我需要从上面的开始日期和结束日期开始按月为该组生成一个数组：

$arr_month['oct_11'] = array(
   'month'   => 'October 2011'
 );
 . 
 . 
 .
$arr_month['feb_11'] = array(
   'month'   => 'Feb 2011'
 );

$arr_month['jan_11'] = array(
   'month'   => 'January 2011'
 );

$arr_month['dec_10'] = array(
   'month'   => 'December 2010'
 );

正如你所看到的，如果我使用这个数组生成一个表，表中应该有11行。

Answer 1

$start = "2010-12-24";
$end = "2011-10-06";

function enumerate($start,$end) {
        $start = strtotime($start);
        $end = strtotime($end . "+1 month");
        $range = range($start,$end,60*60*24*31);
        $formatted = array();
        foreach($range as $date) {
        $key = strtolower(str_replace(" ","_",date("M Y",$date)));
        $formatted[$key] = array(

                        "month" => date('M Y',$date),
                        "amount" => "365"
                );
        }       
        return $formatted;
}

var_dump(enumerate($start,$end));

Answer 2

$start_date = '2010-12-24';
$end_date = '2011-10-06';

function getMonthArray($start_date, $end_date){
    $start_timestamp = strtotime(str_replace('-', '/', $start_date));
    $end_timestamp = strtotime(str_replace('-', '/', $end_date));

    $start_month_timestamp = strtotime(date('F Y', $start_timestamp));
    $current_month_timestamp = strtotime(date('F Y', $end_timestamp));

    $arr_month = array();

    while( $current_month_timestamp >= $start_month_timestamp ) {
        $arr_month[strtolower(date('M_y', $end_timestamp))] = date('F Y', $end_timestamp);
        $end_timestamp = strtotime('-1 month', $end_timestamp);

        $current_month_timestamp = strtotime(date('F Y', $end_timestamp));
    }

    return $arr_month;
}

$arr_month = getMonthArray($start_date, $end_date);

Demo

Answer 3

<?php

$start = strtotime(substr_replace('2010-12-24', '01', -2));
$end = strtotime('2011-10-06');

$time = $start;
$arr_month = array();
while ($time <= $end) {
    $arr_month[strtolower(date('M_y', $time))]['month'] = date('F Y', $time);
    $time += date('t', $time) * 24 * 60 * 60;
}

var_dump($arr_month);

http://ideone.com/ozLOx

PHP生成具有月份和年份显示数量的数组

3 个答案: