此示例演示如何使用Scanner逐行读取文件(它不执行写操作)我不知道为什么在尝试编译时出现错误。有人可以向我解释一下原因吗?我正在使用jcreatorLE和JDK 1.6来运行我的程序:
import java.io.*;
import java.util.Scanner;
public final class File_read {
public static void main(String... aArgs) throws FileNotFoundException {
ReadWithScanner parser = new ReadWithScanner("C:\\Temp\\test.txt");
parser.processLineByLine();
log("Done.");
}
/**
* @param aFileName full name of an existing, readable file.
*/
public ReadWithScanner(String aFileName){
fFile = new File(aFileName);
}
/** Template method that calls {@link #processLine(String)}. */
public final void processLineByLine() throws FileNotFoundException {
Scanner scanner = new Scanner(fFile);
try {
//first use a Scanner to get each line
while ( scanner.hasNextLine() ){
processLine( scanner.nextLine() );
}
}
finally {
//ensure the underlying stream is always closed
scanner.close();
}
}
/**
* Overridable method for processing lines in different ways.
*
* <P>This simple default implementation expects simple name-value pairs, separated by an
* '=' sign. Examples of valid input :
* <tt>height = 167cm</tt>
* <tt>mass = 65kg</tt>
* <tt>disposition = "grumpy"</tt>
* <tt>this is the name = this is the value</tt>
*/
protected void processLine(String aLine){
//use a second Scanner to parse the content of each line
Scanner scanner = new Scanner(aLine);
scanner.useDelimiter("=");
if ( scanner.hasNext() ){
String name = scanner.next();
String value = scanner.next();
log("Name is : " + quote(name.trim()) + ", and Value is : " + quote(value.trim()) );
}
else {
log("Empty or invalid line. Unable to process.");
}
//(no need for finally here, since String is source)
scanner.close();
}
// PRIVATE //
private final File fFile;
private static void log(Object aObject){
System.out.println(String.valueOf(aObject));
}
private String quote(String aText){
String QUOTE = "'";
return QUOTE + aText + QUOTE;
}
}
这是运行它的结果:
--------------------Configuration: <Default>--------------------
C:\Users\administrador\Documents\File_read.java:15: invalid method declaration; return type required
public ReadWithScanner(String aFileName){
^
1 error
Process completed.
答案 0 :(得分:6)
当你从here :-)中提取代码时,你重命名了类而不是构造函数。只允许构造函数没有返回类型。
我建议您重新命名该类或重命名构造函数。
我希望这不是功课。目前,您的教育工作者将有一个轻松的时间来证明抄袭。您至少需要更改变量名称和类名称,您可能还需要重新格式化它,包括更改类中方法的顺序。
如果是家庭作业的话。它不是,对吧? : - )
答案 1 :(得分:3)
你的“ReadWithScanner”构造函数需要匹配类的名称(“File_read”)
public File_read(String aFileName){
fFile = new File(aFileName);
}
答案 2 :(得分:1)
您的类名为File_read
,您的构造函数名为ReadWithScanner
。警告是您的构造函数需要与类命名相同。
答案 3 :(得分:0)
该类的名称是File_read,因此构造函数名称应该是File_read,但是您将名称作为ReadWithScanner,这就是它抱怨的原因。编译器认为它是一个方法名称,因此期望返回类型。