Question

我想知道在一个PHP页面上运行两个（或更多）if语句的最佳方法是什么。这是寻找机票类型和天数的表单的一部分。我需要在一个页面上运行这两个语句，我似乎没有工作，因为一旦它达到真正的声明，它就会停止。我怎样才能让它发挥作用？

<?php
    if($ticket_type=='Child (5 & Under)'){
     echo "
     <select name=\"ticket_type[]\">
       <option value=\"\">Select one...</option>
       <option selected=\"selected\">Child (5 &amp; Under)</option>
       <option>Child (6 - 12)</option>
       <option>Teen (13 - 17)</option>
     </select>";
    }else if($ticket_type=='Child (6 - 12)'){
     echo "
     <select name=\"ticket_type[]\">
       <option value=\"\">Select one...</option>
       <option>Child (5 &amp; Under)</option>
       <option selected=\"selected\">Child (6 - 12)</option>
       <option>Teen (13 - 17)</option>
     </select>";
    }else if($ticket_type=='Teen (13 - 17)'){
     echo "
     <select name=\"ticket_type[]\">
       <option value=\"\">Select one...</option>
       <option>Child (5 &amp; Under)</option>
       <option>Child (6 - 12)</option>
       <option selected=\"selected\">Teen (13 - 17)</option>
     </select>";
    }else{
     echo "
     <select name=\"ticket_type[]\">
       <option value=\"\">Select one...</option>
       <option>Child (5 &amp; Under)</option>
       <option>Child (6 - 12)</option>
       <option>Teen (13 - 17)</option>
     </select>";


  }?>




<?php
        if($days=='1 Day'){
         echo "
         <select name=\"ticket_type[]\">
           <option value="">Select one...</option>
           <option selected=\"selected\">1 Day</option>
           <option>2 Days</option>
           <option>3 out of 4 Days</option>
         </select>";
        }else if($days=='2 Days'){
         echo "
         <select name=\"ticket_type[]\">
           <option value="">Select one...</option>
           <option>1 Day</option>
           <option selected=\"selected\">2 Days</option>
           <option>3 out of 4 Days</option>
         </select>";
        }else if($days=='3 out of 4 Days'){
         echo "
         <select name=\"ticket_type[]\">
           <option value="">Select one...</option>
           <option>1 Day</option>
           <option>2 Days</option>
           <option selected=\"selected\">3 out of 4 Days</option>
         </select>";
        }else{
         echo "
         <select name=\"days[]\">
           <option value="">Select one...</option>
           <option>1 Day</option>
           <option>2 Days</option>
           <option>3 out of 4 Days</option>
         </select>";
        }?>

Answer 1

您可以极大地简化代码：

$options = array(
   'Select One' => 'Select One',
   '1 Day' => '1 Day',
   '2 Days' => '2 Days',
   '3 or more' => '3 or More'
);

echo '<select name="ticket_type[]">';
foreach($options as $key => $val) {
   $select = (($key == $days) ? ' selected="selected"' : '');
   echo "<option value=\"", htmlspecialchars($key), "\"$select>", htmlspecialchars($val), "</option>";
}
echo '</select>';

这样，您只有一个指定了选项的位置，因此如果您将来需要添加更多选项，则只需更改该位置。现在你必须改变你的if（）块的每一部分，这将变得乏味且容易出错。

Answer 2

噢，小伙子......为什么你这么复杂？

<select name="ticket_type[]">
   <option value="">Select one...</option>
   <option <? echo ($ticket_type == 'Child (5 &amp; Under) ? 'selected="selected" : ''; ?>'>Child (5 &amp; Under)</option>
   <option <? echo ($ticket_type == 'Child (6 - 12) ? 'selected="selected" : ''; ?>>Child (6 - 12)</option>
   <option <? echo ($ticket_type == 'Child (13 - 17) ? 'selected="selected" : ''; ?>>Teen (13 - 17)</option>
</select>";

但你真的应该考虑使用ID，所以你不必比较字符串。

Answer 3

哎呀，那有点乱。您应该阅读PHP's Alternative Syntax。

<?php if ($condition): ?>
This is a test..
<?php endif; ?>

在PHP页面上运行多个Else If语句

3 个答案: