Question

我需要根据我的request.GET URL过滤querySet，它将包含字段名称和值。

我的模特：

class AnimalType(Basemodel):  
    name = models.CharField()  
    type = models.ForeignKey(Type) 

class SubAnimalType(Basemodel):  
    name = models.CharField()  
    animaltype = models.ForeignKey(AnimalType) 

class Location(Basemodel):  
    name = models.CharField()  
    country = models.CharField()  

class Animal(Basemodel):  
    name = models.CharField()  
    typeofanimal = models.ForeignKey(SubAnimalType)  
    location = models.ForeignKey(location)

我会得到像"/search/?typeofanimal__animaltype__type__icontains=foo&location__country__iexact=in&food__icontains=hoo"

这样的网址

现在我需要一个通用的功能，它需要args动物模型＆amp;过滤params如下，并应返回过滤的querset。

get_filter_from_filter_params(querySet, filter_params):  
    # logic goes here which should filter fields (i.e typeofanimal  & location ) which are all belongs/related(fk) of the querySet 
    #And should omit the model fields which not belongs to this model(i.e food field)
    return filtered query set # querySet.filter(typeofanimal__animaltype__type__icontains=foo,location__country__iexact=in)

我将调用上面的方法，如

SearchForm(request):   
    q = Animal.objects.all()  
    get_filter_from_filter_params(q, request.GET)

我希望我已经分享了足够的信息。我厌倦了model._meta.get_field（name），它只支持本地字段而不考虑FK字段。

我喜欢将此函数作为通用函数，以便我可以将此函数用于不同的模型。

提前致谢

Answer 1

Animal.objects.filter(**request.GET)

从过滤器参数获取查询集

1 个答案: