Question

我需要一些帮助打印出一个已排序的txt日志文件。除了我不想多次打印出相同的IP号码外，打印没有问题。

这是我的代码。

    text_file = open("access_log.txt")
entire_file = text_file.readlines()
text_file.close()

for line in reversed(entire_file):
    try:
        arr = line.split(' ')
        date = arr[3] 
        print arr[0], "- - ", date[1:], " ",arr[6] 
    except IndexError, e:
        error = e

如您所愿，我只想打印出访问过的IP号码，日期和页面。但只有一次来自类似的IP。

好吧，你可能会看到我是一个初学者=）感谢

Answer 1

# empty set of already seen ips:
seen_ips = set()

with open("access_log.txt") as f:
    for line in lines:
        arr = line.split(' ')
        date = arr[3] 

        # if the ip still not seen, then print and add it to the seen_ips set:
        if arr[0] not in seen_ips:
            print arr[0], "- - ", date[1:], " ",arr[6]
            seen_ips.add(arr[0])
        # else (i.e. ip already seen) ignore and go on with the next line

Answer 2

您可以使用groupby()中的itertools通过您指定的密钥对可迭代进行分组，然后只对密钥（或组中的第一项）进行操作，只要它已排序即可：

split=lambda l: l.split(' ')
for key, group in groupby(sorted(map(split, f)), key=itemgetter(0)):
    line=next(group)
    print key, "- - ", line[3][1:], " ", line[6]

使用Python对txt文件进行排序

2 个答案: