Question

我正在尝试获取一个文本文件并将整数放在文件中并将它们传输到一个向量中，在该向量中可以读入不同的函数。

这是我到目前为止所做的：

int main(int argc, char *argv[] )
{
vector<int> buff;
argv[1] = "input_24_0.txt";

if (argc < 2)
{
    std::cout << "usage: " << argv[0] << " <filename>\n";
    return 2;
}
std::ifstream fin(argv[1]);
if (fin)
{
    std::stringstream ss;
    // this copies the entire contents of the file into the string stream
    ss << fin.rdbuf();
    // get the string out of the string stream
    std::string contents = ss.str();
    std::cout << contents;
    // construct the vector from the string.
    std::vector<int> buff(contents.begin(), contents.end());
}
else 
{
    std::cout << "Couldn't open " << argv[1] << "\n";
    return 1;
}

clock_t t1, t2, t3, t4;

int maxSum;

t1 = clock();
maxSum = maxSubSum1(buff);
cout << "MaxSubSum1 is " <<  maxSum << endl;
cout << double( clock() - t1 )
/ (double)CLOCKS_PER_SEC<< " seconds." << endl;
t1 = clock() - t1;

t2 = clock();
maxSum = maxSubSum2( buff );
cout << "MaxSubSum2 is " <<  maxSum << endl;
cout << double( clock() - t2)
/ (double)CLOCKS_PER_SEC<< " seconds." << endl;
t2 = clock() - t2;

t3 = clock();
maxSum = maxSubSum3(buff );
cout << "MaxSubSum3 is " <<  maxSum << endl;
cout << double( clock() - t3 )
/ (double)CLOCKS_PER_SEC<< " seconds." << endl;
t3 = clock() - t3;

t4 = clock();
maxSum = maxSubSum4( buff );
cout << "MaxSubSum4 is " <<  maxSum << endl;
cout << double( clock() - t4 )
/ (double)CLOCKS_PER_SEC<< " seconds." << endl;
t4 = clock() - t4;

system("pause");

return 0;
 }

Answer 1

如果文件中的数字用空格分隔，则可以执行以下操作：

 std::ifstream iStream;
 iStream.open("filename.ext");
 int tempVariable;

 if (iStream) {
   while (iStream >> tempVariable) {
      // Any routines to check the value of the number if necessary
      vector.push_back(tempVariable);
   }
   iStream.close();
 }
 else
   // Error routine

如果数字没有用空格分隔，你可以使用你的字符串流方法，并循环流将每个char转换成它的十进制值。

如何从文件中获取整数并将它们放在int向量中？

1 个答案: