我有一个http post连接方法,如下所示:
request = [[NSMutableURLRequest alloc] initWithURL:[NSURL URLWithString:url]];
[request setHTTPMethod:method];
[request setValue:contentType forHTTPHeaderField:@"Content-Type"];
[request setValue:@"DataType" forHTTPHeaderField:dataType];
[request setValue:[NSString stringWithFormat:@"%d", [data length]] forHTTPHeaderField:@"Content-length"];
[request setHTTPBody:[data dataUsingEncoding:NSUTF8StringEncoding]];
[[NSURLConnection alloc] initWithRequest:request delegate:self];
response = nil;
NSError *error = [[NSError alloc] init];
NSData *responseData = [NSURLConnection sendSynchronousRequest:request returningResponse:&response error:&error];
[request release];
result = [[NSString alloc] initWithData:responseData encoding:NSUTF8StringEncoding];
responseCode = [response statusCode];
[error release];
if(responseCode == 200) {
[self connectionCompletedHere];
}
else
{
[self connectionFailedHere];
}
它工作正常,但我得到像__NSAutoreleaseNoPool()的控制台消息:类NSURL的对象0x62c3b80自动释放没有池到位 - 只是泄漏。
使用泄漏工具我将其缩小到2行,导致泄漏:
[[NSURLConnection alloc] initWithRequest:request delegate:self];
和
NSData *responseData = [NSURLConnection sendSynchronousRequest:request returningResponse:&response error:&error];
我做错了什么?
提前致谢
答案 0 :(得分:0)
不要分配/初始化/释放NSError,它是一个引用参数,只需声明它并传递它的地址:
NSError *error;
重新编写代码:
...
response = nil;
NSError *error;
NSData *responseData = [NSURLConnection sendSynchronousRequest:request returningResponse:&response error:&error];
[request release];
result = [[NSString alloc] initWithData:responseData encoding:NSUTF8StringEncoding];
responseCode = [response statusCode];
if(responseCode == 200) {
...