Question

我有这个SQL代码：

SELECT EXTRACT(MONTH FROM timestamp) AS StatMonth, timestamp
  FROM server_stats
 GROUP BY StatMonth
 ORDER BY StatMonth DESC;

架构：

CREATE TABLE IF NOT EXISTS `server_stats` (
  `id` int(11) NOT NULL AUTO_INCREMENT,
  `timestamp` int(11) NOT NULL,
  `players_online` bigint(20) NOT NULL,
  `active_players` bigint(20) NOT NULL,
  `total_copper` bigint(20) NOT NULL,
  `total_items` bigint(20) NOT NULL,
  `total_item_weight` bigint(20) NOT NULL,
  `total_houses` bigint(20) NOT NULL,
  `total_boats` bigint(20) NOT NULL,
  `total_pets` bigint(20) NOT NULL,
  `total_experience` bigint(20) NOT NULL,
  PRIMARY KEY (`id`)
) ENGINE=MyISAM  DEFAULT CHARSET=latin1 AUTO_INCREMENT=63 ;

示例数据：

INSERT INTO `server_stats` (`id`, `timestamp`, `players_online`, `active_players`,
        `total_copper`, `total_items`, `total_item_weight`, `total_houses`,
        `total_boats`, `total_pets`, `total_experience`) VALUES
(53, 1317288600, 227, 718, 155037828, 68231283, 25169498, 14822, 2112, 683, 7776385802),
(54, 1317290400, 224, 718, 155038479, 68233576, 25163526, 14822, 2112, 683, 7776669410),
(55, 1317292200, 215, 718, 155100860, 68239613, 25160397, 14822, 2112, 683, 7776933725),
(56, 1317294000, 201, 717, 155095895, 68240842, 25159809, 14822, 2112, 683, 7777196134),
(57, 1317295800, 204, 718, 155090280, 68248539, 25170275, 14822, 2112, 683, 7777419238),
(58, 1317297600, 194, 718, 155105906, 68259213, 25163212, 14823, 2112, 683, 7777657681),
(59, 1317682800, 230, 724, 157323143, 68731571, 25185326, 14908, 2119, 692, 7834358253),
(60, 1317684600, 213, 724, 157323178, 68733325, 25186412, 14908, 2119, 692, 7834637558),
(61, 1317686400, 219, 724, 157314147, 68737824, 25197057, 14908, 2119, 692, 7834904982),
(62, 1317688200, 225, 725, 157329100, 68736384, 25190554, 14909, 2119, 692, 7835169244);

我使用上面的SELECT语句来显示每个月。在这种情况下，应该是9月（9）和10月（10）。但是，它只显示9月，而不是10月。

有人可以向我解释一下吗？

Answer 1

如果你使用MONTH FROM from_unixtime(timestamp)，这在MySQL 5.1中可以正常工作。

SQL Group By of Date not Working

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