Question

我的行动很简单：

 [HttpPost]
    public virtual ActionResult New(Feedback feedback)
    {
        feedback.CreatedDate = DateTime.UtcNow;

        if (TryValidateModel(feedback))
        {
            FeedbackRepository.Add(feedback);
            var model = new Feedback
                            {                                   
                                SuccessfullyPosted = true
                            };

            return PartialView(MVC.Shared.Views._FeedBackForm, model);
        }

        return PartialView(MVC.Shared.Views._FeedBackForm, feedback);
    }

因此，想法是如果接收的数据正在验证罚款，则返回具有空反馈实体的部分视图。事实是，如果我看一下萤火虫的反应，我会看到旧的价值回归，这有多奇怪？

表格如下：

@using (Ajax.BeginForm(MVC.Feedback.New(), new AjaxOptions
                                                                 {
                                                                     UpdateTargetId = "contactsForm",
                                                                     HttpMethod = "post"
                                                                 }))
{           
    
        

            
    
        @Html.LabelFor(x => x.FirstName)
        @Html.EditorFor(x => x.FirstName)
        @Html.ValidationMessageFor(x => x.FirstName)
    
        @Html.LabelFor(x => x.LastName)
        @Html.EditorFor(x => x.LastName)
        @Html.ValidationMessageFor(x => x.LastName)
    
        @Html.LabelFor(x => x.Email)
        @Html.EditorFor(x => x.Email)
        @Html.ValidationMessageFor(x => x.Email)
    
        @Html.LabelFor(x => x.Phone)
        @Html.EditorFor(x => x.Phone)
        @Html.ValidationMessageFor(x => x.Phone)                       
    
        @Html.LabelFor(x => x.Comments)

        @Html.TextAreaFor(x => x.Comments, new { cols = 60, rows = 10 })
        @Html.ValidationMessageFor(x => x.Comments)
    
    if (Model.SuccessfullyPosted)
    {
    
        Feedback sent successfully.
    }
    
        
}

是否有可能以某种方式禁用此行为以及PartialView(MVC.Shared.Views._FeedBackForm, model)如何设法获得不同的模型？

更新：我看到stackoverflow从视图中获取所有html，但无法找到解决方法。

Answer 1

ModelState是模型值的主要供应商。即使您将模型传递给View或PartialView，EdiorFor也会首先查看ModelState相应的属性值，如果它不存在，则只会进入模型本身。发布到控制器时会填充ModelState（旧反馈）。即使您创建新的反馈并将其作为模型传递，ModelState已包含先前发布的反馈的值，因此您在客户端上获取旧值。在成功发布结果之前清除模型状态将对您有所帮助。

FeedbackRepository.Add(feedback);
var model = new Feedback
                {                                   
                   SuccessfullyPosted = true
                 };
ModelState.Clear(); // force to use new model values
return PartialView(MVC.Shared.Views._FeedBackForm, model);

有关相关情况的示例，请参阅this和this链接

即使我传递了另一个模型，Ajax.BeginForm响应也包含以前的值

1 个答案: