我要做的是创建一个视图,选择empno,ename,deptno将列empno重命名为Employee_ID,ename to Employee,deptno重命名为Department_ID 为什么我有这些问题的任何想法?
SQL> create view DEPT20 AS
2 select empno,ename,deptno (employee_id, employee, Department_ID) from emp
3 where deptno = 20
4 with check option constraint emp_dept_20;
select empno,ename,deptno (employee_id, employee, Department_ID) from emp
*
ERROR at line 2:
ORA-00904: "DEPTNO": invalid identifier
我知道它的存在,为什么我会收到错误?
SQL> select empno, ename, deptno from emp;
EMPNO ENAME DEPTNO
---------- ---------- ----------
7839 KING 10
7698 BLAKE 30
7782 CLARK 10
7566 JONES 20
7654 MARTIN 30
7499 ALLEN 30
7844 TURNER 30
7900 JAMES 30
7521 WARD 30
7902 FORD 20
7369 SMITH 20
EMPNO ENAME DEPTNO
---------- ---------- ----------
7788 SCOTT 20
7876 ADAMS 20
7934 MILLER 10
8888 Stuttle 40
15 rows selected.
SQL>
答案 0 :(得分:2)
看起来您正在尝试重命名列。我认为您需要像以下一样
select empno as employee_id, ename as employee,deptno as department_id from emp
答案 1 :(得分:2)
如果你试试这个,也许会有所帮助:
SELECT
empno as employee_id,
ename as employee,
deptno as Department_ID
FROM emp ...
答案 2 :(得分:1)
为什么不尝试这样 -
... select empno as employee_id, ename as employee, deptno as Department_ID
from emp where Department_ID = 20 ...