Question

在c ++中是否有一种方法可以使单个变量保持相同的值，并且在添加时，它会使用新值添加其最后一个值？例如，我正在编写一个程序，用户可以在该程序中输入他们当天收到的“支票”和“存款”，并且在一天结束时程序将让用户知道他一整天都在做多少< / p>

这是我到目前为止所拥有的

#include <cstdlib>
#include <iostream>

using namespace std;

int main(int argc, char *argv[])
{

system("Color 0E");
int cashBalance = 1000;
int check;
int depo;
double toDepo = depo * 0.3;
double totalDepo = depo - toDepo;
int loop = 5;
int choice;

cout << "check = 1, deposit = 2, add = 3, clear the screen = 4, close = 0\n" << endl;
while (loop == 5){
  cout << "Would you like to enter a depoist or a check?\n" << endl;
  cin >> choice;
  //determines whether or not to close the program
  if(choice == 0 || depo == 0 || check == 0){
  return 0;          
  }//end close if
  //choses which type of input to make
    if( choice == 1){
      cout << "Please enter check\n" << endl;    
      cin >> check;
    } else if(choice == 2){
      cout << "Please enter deposit\n" << endl;
      cin >> depo;
    }//end if
    if(choice == 3 || depo == 3 || check == 3){
    cout << "Total = " << (cashBalance - check) + totalDepo << endl;
  }
  //clear the console screen
  if(choice == 4 || depo == 4 || check == 4){
  system("cls");
  cout << "check = 1, deposit = 2, add = 3, clear the screen = 4, close = 0\n" << endl;
  }
}//end while loop
system("PAUSE");
return EXIT_SUCCESS;
}//end of program

问题是我需要变量“check”和“depo”才能添加用户的第一个值和第二个值来获取新值。现在它只是显示用户插入的最后一个值。

Answer 1

是

您可以将旧值添加到旧值中：

oldValue += newValue;

或者，您也可以这样做：

oldValue = oldValue + newValue;

Answer 2

变量只能显示用户insert.suppose

的最后一个值

int a=5;
a=a+5;
cout<<a;

output will be 10，因为新值会覆盖前一个地址。

c ++中的变量可以添加旧值加上新值吗？

2 个答案: