Question

我目前有代码：

fleechance = random.randrange(1,5)
print fleechance
if fleechance == 1 or 2:
    print "You failed to run away!"
elif fleechance == 4 or 3:
    print "You got away safely!"

fleechance一直打印为3或4，但我继续得到结果“你没能逃跑！”谁能告诉我为什么会这样呢？

Answer 1

表达式fleechance == 1 or 2相当于(fleechance == 1) or (2)。数字2始终被视为“真实”。

试试这个：

if fleechance in (1, 2):

编辑：在你的情况下（只有2种可能性），以下情况会更好：

if fleechance <= 2:
    print "You failed to run away!"
else:
    print "You got away safely!"

Answer 2

尝试

if fleechance == 1 or fleechance == 2:
    print "You failed to run away!"
elif fleechance == 4 or fleechance == 3:
    print "You got away safely!"

或者，如果这些是唯一的可能性，你可以做

if fleechance <= 2:
    print "You failed to run away!"
else:
    print "You got away safely!"

Answer 3

if语句按设计工作，问题是操作顺序导致此代码执行除您想要的操作之外的其他操作。

最简单的解决方法是：

if fleechance == 1 or fleechance == 2:
    print "You failed to run away!"
elif fleechance == 3 or fleechance == 4:
    print "You got away safely!"

Answer 4

因为您没有询问fleechance是1还是fleechance是2;你问是否

fleechance是1，或
2非零。

当然，条件的第二部分总是如此。尝试

if fleechance == 1 or fleechance == 2:
    ...

Answer 5

你编写if语句的方式是错误的。你告诉python检查fleechance是否等于1是否为真，或者2是否为真。在条件中，非零整数始终表示为真。你应该写道：

fleechance = random.randrange(1,5)
print fleechance
if fleechance == 1 or fleechance == 2:
    print "You failed to run away!"
elif fleechance == 4 or fleechance == 3:
    print "You got away safely!"

Python if语句不能按预期工作

5 个答案: