我正在制作一个Caesar密码,我想在循环中制作字母,例如,如果字母'z'需要移位,它应该返回'a'表示大写和小写。
//Array that holds each char in the plaintext inputed is declared and initiated
char[] chars = plainTextInput.ToCharArray();
//For loop that will go through each letter and change the value of each letter by adding the shiftAmount
for (int i = 0; i < plainTextInput.Length; ++i)
{
chars[i] = (char)(((int)chars[i]) + shiftAmount);
if (chars[i] >= 97 && chars[i] <= 122)
{
if (chars[i] > 122)
{
int x = chars[i] - 123;
chars[i] = (char)((int)(97 + x));
}
}
}
//Variable for ciphertext output holds char array chars as a string
cipherTextOutput = new string(chars);
如果我输入'xyz'
并换一个,我会'yz{'
。
答案 0 :(得分:1)
使用模运算:
new_pos = (current_pos + shift) % 26
current_pos
必须是相对字母位置(例如:a=0, b=1... z=25
)。类似的东西:
if ('A' <= c && c <= 'Z') // uppercase
{
current_pos = (int) c - (int) 'A';
}
else if ('a' <= c && c <= 'z') // lowercase
{
current_pos = (int) c - (int) 'a';
}
话虽如此,我希望这只是您正在玩的代码,而不是在实际代码中使用的代码。