我有两个关联数组。我需要减去($ price - $ tax)以获得$ total总价:
$price['lunch'] = array("food" => 10, "beer"=> 6, "wine" => 9);
$price['dinner'] = array("food" => 15, "beer"=> 10, "wine" => 10);
$tax['lunch'] = array("food" => 2, "beer"=> 3, "wine" => 2);
$tax['dinner'] = array("food" => 4, "beer"=> 6, "wine" => 4);
所需的结果数组:
$result['lunch'] = (['food'] => 8, ['beer'] =>3, ['wine'] => 7 )
$result['dinner'] = (['food'] => 11, ['beer'] =>4, ['wine'] => 6 )
我正在尝试跟随函数和array_map无效:
function minus($a, $b) {
return $a - $b;
}
foreach ($price as $value)
{
$big = $value;
foreach($tax as $v) {
$small = $v;
$e[] = array_map("minus",$big, $small);
}
}
上面我得到四个数组(第一个和最后一个是正确的)所以它不正确。感谢您的任何信息!
答案 0 :(得分:4)
您可以使用键而不是数组映射进行比较。使用双重foreach,您可以做任意数量的膳食和食物类型:
foreach(array_keys($price) as $meal)
{
foreach(array_keys($price[$meal]) as $type)
{
$e[$meal][$type] = $price[$meal][$type] - $tax[$meal][$type];
}
}
请注意,此代码不会注意膳食或食物类型中缺少的物品......
答案 1 :(得分:1)
如果$price
和$tax
的结构始终相等,则可以使用以下代码:
<?php
$price['lunch'] = array("food" => 10, "beer"=> 6, "wine" => 9);
$price['dinner'] = array("food" => 15, "beer"=> 10, "wine" => 10);
$tax['lunch'] = array("food" => 2, "beer"=> 3, "wine" => 2);
$tax['dinner'] = array("food" => 4, "beer"=> 6, "wine" => 4);
$result = array();
foreach( $price as $what => $value)
{
foreach( $value as $food => $foodPrice )
{
$result[$what][$food] = $foodPrice - $tax[$what][$food];
}
}
<强>结果:强>
print_r($result);
Array
(
[lunch] => Array
(
[food] => 8
[beer] => 3
[wine] => 7
)
[dinner] => Array
(
[food] => 11
[beer] => 4
[wine] => 6
)
)