Question

如何将YUI3 sendRequest应用于数据源以返回预定义对象而不是普通对象？

例如，我有这个Base类及其方法：

function Student(id, name){
   this.id = id;
   this.name = name;
}
Context.prototype.setId   = function(id){ this.id = id; };
Context.prototype.setName = function(name){ this.name = name; };
Context.prototype.getId   = function(){ return this.id; };
Context.prototype.getName = function(){ return this.name; };

我有这个代码从API检索数据，规范化它并将数据作为对象返回：

var studApiDataSource = new Y.DataSource.Get({source: API_URL});

studApiDataSource.plug(Y.Plugin.DataSourceJSONSchema, {
  schema: {
    resultListLocator: "response.student",
    resultFields: ["id","name"]
  }
});

var myCallback = function(e) {
  Y.Array.each(e.response.results, function(stud){
    Y.log(stud.id+' '+stud.name);
  }
}

studApiDataSource.sendRequest({
  request: "?cmd=getStudents",
  callback: {
    success: myCallback,
    failure: function (e) { }
  }
});

studApiDataSource.sendRequest（）检索并传递给myCallback的对象数组是普通对象，具有id和name属性。但是，我希望它们是Student对象，它们的成员函数也是（getId，getName等）

Answer 1

我不确定我是否完全明白，但你可以做以下事情。

var studentJSON = "{\"id\": 17, \"name\":\"my name is\"}";
function Student(obj){
  this.name = obj.name;
  this.id = obj.id;
}
Student.prototype.setId   = function(id){ this.id = id; };
Student.prototype.setName = function(name){ this.name = name; };
Student.prototype.getId   = function(){ return this.id; };
Student.prototype.getName = function(){ return this.name; };

YUI().use('json-parse', 'json-stringify', function (Y) {

    try {

        var stud = new Student(Y.JSON.parse(studentJSON));
        alert(stud.getId());
    }
    catch (e) {
        alert(e);
    }

});

YUI3数据源返回自定义对象

1 个答案: