JSON：如何处理这样的JSON响应？

Question

这是响应 我想知道如何处理像这样的JSON响应？ 这是一个JSONArray，但没有名字 以下是回复：

[[84,"sinat","qq357068756@163.com"],[88,"msn","qq357068756@hotmail.com"],[89,"163t","qq357068756@hotmail.com"],[90,"mail","qq357068756@hotmail.com"],[93,"mail","qq357068756@163.com"]]

Answer 1

数据不是JSONObject，而是JSONArray！

String json_value = '[[84,"sinat","qq357068756@163.com"],[88,"msn","qq357068756@hotmail.com"],[89,"163t","qq357068756@hotmail.com"],[90,"mail","qq357068756@hotmail.com"],[93,"mail","qq357068756@163.com"]]';

JSONArray json_array = new JSONArray(json_value);

并像

一样走过去

for(int i = 0; i < json_array.length(); i++){
    Log.d("Current index: "+i,"Current value: "+json_array.getJSONArray(i).toString());
}