Question

在我的代码中我发送了像这样的json数据

ByteArrayOutputStream baos = new ByteArrayOutputStream();
                        imgbmp.compress(Bitmap.CompressFormat.PNG, 90, baos);
                        byte[] b = baos.toByteArray();
                        String encodedImage = Base64.encodeBytes(b);
                        jsonstr = new JSONStringer().object().key("Text")
                                .value(msg).key("Files").array().object().key(
                                        "ContentType").value("image/png").key(
                                        "Content").value(encodedImage)
                                .endObject().endArray().key("AuthToken").value(token)
                                .endObject();

StringEntity entity = new StringEntity(jsonstr.toString());
                    entity.setContentType("application/json;charset=UTF-8");
                    entity.setContentEncoding(new BasicHeader(HTTP.CONTENT_TYPE,"application/json;charset=UTF-8"));
                    request.setEntity(entity);
                    DefaultHttpClient httpClient = new DefaultHttpClient();

                    HttpResponse res = httpClient.execute(request);

，我在执行HttpClient时遇到此错误

09-30 11:56:21.571: INFO/Request(22161): org.apache.http.client.methods.HttpPost@468613b0
09-30 11:56:21.586: INFO/JSON ANS(22161): <Fault xmlns="http://schemas.microsoft.com/ws/2005/05/envelope/none"><Code><Value>Receiver</Value><Subcode><Value xmlns:a="http://schemas.microsoft.com/net/2005/12/windowscommunicationfoundation/dispatcher">a:InternalServiceFault</Value></Subcode></Code><Reason><Text xml:lang="en-US">The input is not a valid Base-64 string as it contains a non-base 64 character, more than two padding characters, or a non-white space character among the padding characters. </Text></Reason><Detail><ExceptionDetail xmlns="http://schemas.datacontract.org/2004/07/System.ServiceModel" xmlns:i="http://www.w3.org/2001/XMLSchema-instance"><HelpLink i:nil="true"/><InnerException i:nil="true"/><Message>The input is not a valid Base-64 string as it contains a non-base 64 character, more than two padding characters, or a non-white space character among the padding characters. </Message><StackTrace>   at System.Convert.FromBase64String(String s)&#xD;
09-30 11:56:21.586: INFO/JSON ANS(22161):    at Zoodig.Core.WebServices.DataContracts.FileContract.GetStream()&#xD;
09-30 11:56:21.586: INFO/JSON ANS(22161):    at Zoodig.WebServices.Services.AthletesService.PostUpdate(PostUpdateContract data)&#xD;
09-30 11:56:21.586: INFO/JSON ANS(22161):    at SyncInvokePostUpdate(Object , Object[] , Object[] )&#xD;
09-30 11:56:21.586: INFO/JSON ANS(22161):    at System.ServiceModel.Dispatcher.SyncMethodInvoker.Invoke(Object instance, Object[] inputs, Object[]&amp; outputs)&#xD;
09-30 11:56:21.586: INFO/JSON ANS(22161):    at System.ServiceModel.Dispatcher.DispatchOperationRuntime.InvokeBegin(MessageRpc&amp; rpc)&#xD;
09-30 11:56:21.586: INFO/JSON ANS(22161):    at System.ServiceModel.Dispatcher.ImmutableDispatchRuntime.ProcessMessage5(MessageRpc&amp; rpc)&#xD;
09-30 11:56:21.586: INFO/JSON ANS(22161):    at System.ServiceModel.Dispatcher.ImmutableDispatchRuntime.ProcessMessage41(MessageRpc&amp; rpc)&#xD;
09-30 11:56:21.586: INFO/JSON ANS(22161):    at System.ServiceModel.Dispatcher.ImmutableDispatchRuntime.ProcessMessage4(MessageRpc&amp; rpc)&#xD;
09-30 11:56:21.586: INFO/JSON ANS(22161):    at System.ServiceModel.Dispatcher.ImmutableDispatchRuntime.ProcessMessage31(MessageRpc&amp; rpc)&#xD;
09-30 11:56:21.586: INFO/JSON ANS(22161):    at System.ServiceModel.Dispatcher.ImmutableDispatchRuntime.ProcessMessage3(MessageRpc&amp; rpc)&#xD;
09-30 11:56:21.586: INFO/JSON ANS(22161):    at System.ServiceModel.Dispatcher.ImmutableDispatchRuntime.ProcessMessage2(MessageRpc&amp; rpc)&#xD;
09-30 11:56:21.586: INFO/JSON ANS(22161):    at System.ServiceModel.Dispatcher.ImmutableDispatchRuntime.ProcessMessage11(MessageRpc&amp; rpc)&#xD;
09-30 11:56:21.586: INFO/JSON ANS(22161):    at System.ServiceModel.Dispatcher.ImmutableDispatchRuntime.ProcessMessage1(MessageRpc&amp; rpc)&#xD;
09-30 11:56:21.586: INFO/JSON ANS(22161):    at System.ServiceModel.Dispatcher.MessageRpc.Process(Boolean isOperationContextSet)</StackTrace><Type>System.FormatException</Type></ExceptionDetail></Detail></Fault>

如果有人能够理解这一点并告诉我这里发生了什么......我犯了哪些错误......以及为什么我会收到错误？

谢谢。 MKJParekh

Answer 1

我得到了答案...... 我没有犯任何错误

这是org.json的问题

我切换到另一个......并且一切正常

nesting too deep in JSON... should I switch to XML?

Answer 2

查看代码，您正在使用enimg将图像数据添加到JSON而不是encodedImage。如果这是一个削减＆amp;在您的问题中粘贴错误，然后我怀疑您的Base64编码可能存在问题。您是否尝试过使用encodeToString()的{{1}}方法？

即使您需要支持早于8的API版本，这也将证明它是否是Base64错误，并且一旦您确定您将知道必须修复的内容。

Answer 3

不要使用json传递文件/图像。如果文件/图像很大，你将会出现“内存不足”错误。

使用Base64编码的图像字符串将Json数据发送到服务器时出错

3 个答案: