Question

我想知道是否可以对我的类进行注释，以便第一次编组遇到一个对象，它会生成一个相应类型的XML元素，但是任何其他任何后续对该对象的引用都将具有XML IDREF条目创建？

Answer 1

您可以利用JAXB的XmlAdapter概念执行以下操作：

<强> input.xml中

以下是我将用于此示例的XML文档。第3个phone-number条目是对第1个phone-number条目的引用，第5个phone-number条目是对第4个条目的引用。

<?xml version="1.0" encoding="UTF-8" standalone="yes"?>
<customer>
    <phone-number id="A">
        <number>555-AAAA</number>
    </phone-number>
    <phone-number id="B">
        <number>555-BBBB</number>
    </phone-number>
    <phone-number id="A"/>
    <phone-number xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance" xsi:type="work-phone-number" id="W">
        <number>555-WORK</number>
        <extension>1234</extension>
    </phone-number>
    <phone-number xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance" xsi:type="work-phone-number" id="W"/>
</customer>

<强>客户

customer类维护一组PhoneNumber个对象。 PhoneNumber的相同实例可能会在集合中多次出现。

package forum7587095;

import java.util.List;

import javax.xml.bind.annotation.XmlElement;
import javax.xml.bind.annotation.XmlRootElement;

@XmlRootElement
public class Customer {

    private List<PhoneNumber> phoneNumbers;

    @XmlElement(name="phone-number")
    public List<PhoneNumber> getPhoneNumbers() {
        return phoneNumbers;
    }

    public void setPhoneNumbers(List<PhoneNumber> phoneNumbers) {
        this.phoneNumbers = phoneNumbers;
    }

}

<强> ******中国

这是一个可以出现在文档本身或作为参考的类。这将使用XmlAdapter来处理。使用@XmlJavaTypeAdapter注释配置XmlAdapter。由于我们在类型/类级别指定了此适配器，因此它将应用于引用PhoneNumber类的所有属性：

package forum7587095;

import javax.xml.bind.annotation.adapters.XmlJavaTypeAdapter;

@XmlJavaTypeAdapter(PhoneNumberAdapter.class)
public class PhoneNumber {

    private String id;
    private String number;

    public String getId() {
        return id;
    }

    public void setId(String id) {
        this.id = id;
    }

    public String getNumber() {
        return number;
    }

    public void setNumber(String number) {
        this.number = number;
    }

    @Override
    public boolean equals(Object arg0) {
        if(null == arg0 || arg0.getClass() != this.getClass()) {
            return false;
        }
        PhoneNumber test = (PhoneNumber) arg0;
        if(!equals(id, test.getId())) {
            return false;
        }
        return equals(number, test.getNumber());
    }

    protected boolean equals(String control, String test) {
        if(null == control) {
            return null == test;
        } else {
            return control.equals(test);
        }
    }

    @Override
    public int hashCode() {
        return id.hashCode();
    }

}

<强> WorkPhoneNumber

根据您的评论，我添加了PhoneNumber的子类。

package forum7587095;

public class WorkPhoneNumber extends PhoneNumber {

    private String extension;

    public String getExtension() {
        return extension;
    }

    public void setExtension(String extension) {
        this.extension = extension;
    }

    @Override
    public boolean equals(Object arg0) {
        if(!super.equals(arg0)) {
            return false;
        }
        return equals(extension, ((WorkPhoneNumber) arg0).getExtension());
    }

}

<强> PhoneNumberAdapter

以下是XmlAdapter的实施。请注意，如果之前看过PhoneNumber对象，我们必须维护。如果有，我们只填充id对象的AdaptedPhoneNumber部分。

package forum7587095;

import java.util.ArrayList;
import java.util.HashMap;
import java.util.List;
import java.util.Map;

import javax.xml.bind.annotation.XmlAttribute;
import javax.xml.bind.annotation.XmlSeeAlso;
import javax.xml.bind.annotation.XmlType;
import javax.xml.bind.annotation.adapters.XmlAdapter;

public class PhoneNumberAdapter extends XmlAdapter<PhoneNumberAdapter.AdaptedPhoneNumber, PhoneNumber>{

    private List<PhoneNumber> phoneNumberList = new ArrayList<PhoneNumber>();
    private Map<String, PhoneNumber> phoneNumberMap = new HashMap<String, PhoneNumber>();

    @XmlSeeAlso(AdaptedWorkPhoneNumber.class)
    @XmlType(name="phone-number")
    public static class AdaptedPhoneNumber {
        @XmlAttribute public String id;
        public String number;

        public AdaptedPhoneNumber() {
        }

        public AdaptedPhoneNumber(PhoneNumber phoneNumber) {
            id = phoneNumber.getId();
            number = phoneNumber.getNumber();
        }

        public PhoneNumber getPhoneNumber() {
            PhoneNumber phoneNumber = new PhoneNumber();
            phoneNumber.setId(id);
            phoneNumber.setNumber(number);
            return phoneNumber;
        }

    }

    @XmlType(name="work-phone-number")
    public static class AdaptedWorkPhoneNumber extends AdaptedPhoneNumber {

        public String extension;

        public AdaptedWorkPhoneNumber() {
        }

        public AdaptedWorkPhoneNumber(WorkPhoneNumber workPhoneNumber) {
            super(workPhoneNumber);
            extension = workPhoneNumber.getExtension();
        }

        @Override
        public WorkPhoneNumber getPhoneNumber() {
            WorkPhoneNumber phoneNumber = new WorkPhoneNumber();
            phoneNumber.setId(id);
            phoneNumber.setNumber(number);
            phoneNumber.setExtension(extension);
            return phoneNumber;
        }
}

    @Override
    public AdaptedPhoneNumber marshal(PhoneNumber phoneNumber) throws Exception {
        AdaptedPhoneNumber adaptedPhoneNumber;
        if(phoneNumberList.contains(phoneNumber)) {
            if(phoneNumber instanceof WorkPhoneNumber) {
                adaptedPhoneNumber = new AdaptedWorkPhoneNumber();
            } else {
                adaptedPhoneNumber = new AdaptedPhoneNumber();
            }
            adaptedPhoneNumber.id = phoneNumber.getId();
        } else {
            if(phoneNumber instanceof WorkPhoneNumber) {
                adaptedPhoneNumber = new AdaptedWorkPhoneNumber((WorkPhoneNumber)phoneNumber);
            } else {
                adaptedPhoneNumber = new AdaptedPhoneNumber(phoneNumber);
            }
            phoneNumberList.add(phoneNumber);
        }
        return adaptedPhoneNumber;
    }

    @Override
    public PhoneNumber unmarshal(AdaptedPhoneNumber adaptedPhoneNumber) throws Exception {
        PhoneNumber phoneNumber = phoneNumberMap.get(adaptedPhoneNumber.id);
        if(null != phoneNumber) {
            return phoneNumber;
        }
        phoneNumber = adaptedPhoneNumber.getPhoneNumber();
        phoneNumberMap.put(phoneNumber.getId(), phoneNumber);
        return phoneNumber;
    }

}

<强>演示

为了确保整个XmlAdapter和marshal操作使用unmarshal的相同实例，我们必须在Marshaller和Unmarshaller上专门设置XmlAdapter的实例。 package forum7587095; import java.io.File; import javax.xml.bind.JAXBContext; import javax.xml.bind.Marshaller; import javax.xml.bind.Unmarshaller; public class Demo { public static void main(String[] args) throws Exception { JAXBContext jc = JAXBContext.newInstance(Customer.class); Unmarshaller unmarshaller = jc.createUnmarshaller(); unmarshaller.setAdapter(new PhoneNumberAdapter()); File xml = new File("src/forum7587095/input.xml"); Customer customer = (Customer) unmarshaller.unmarshal(xml); System.out.println(customer.getPhoneNumbers().get(0) == customer.getPhoneNumbers().get(2)); System.out.println(customer.getPhoneNumbers().get(3) == customer.getPhoneNumbers().get(4)); Marshaller marshaller = jc.createMarshaller(); marshaller.setProperty(Marshaller.JAXB_FORMATTED_OUTPUT, true); marshaller.setAdapter(new PhoneNumberAdapter()); marshaller.marshal(customer, System.out); } }：

true
true
<?xml version="1.0" encoding="UTF-8" standalone="yes"?>
<customer>
    <phone-number id="A">
        <number>555-AAAA</number>
    </phone-number>
    <phone-number id="B">
        <number>555-BBBB</number>
    </phone-number>
    <phone-number id="A"/>
    <phone-number xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance" xsi:type="work-phone-number" id="W">
        <number>555-WORK</number>
        <extension>1234</extension>
    </phone-number>
    <phone-number xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance" xsi:type="work-phone-number" id="W"/>
</customer>

<强>输出

{{1}}

了解更多信息

JAXB最初可以通过收容进行封送，然后通过@XmlIDREF封送后续引用吗？

1 个答案: