Xsl:我如何根据总和进行分组和排序?

时间:2009-04-17 00:04:39

标签: xslt

我有以下xml

 <ResultCollection>
  <Result Id="551550" Pass="23" Fail="0" Owner="Dong"/>
  <Result Id="551565" Pass="4" Fail="3" Owner="Dong"/>
  <Result Id="551567" Pass="61" Fail="0" Owner="Mei"/>
  <Result Id="551580" Pass="10" Fail="1" Owner="Dong"/>  
  <Result Id="551580" Pass="0" Fail="4" Owner="Sen"/>  
  <Result Id="551548" Pass="1" Fail="12" Owner="Sen"/>
</ResultCollection>

我有一个生成以下摘要的xsl

Owner   Total   Pass    Fail
Dong    41  37  4
Mei     61  61  0
Sen     17  1   16

如何根据通过或失败对此结果进行排序?

我的xsl看起来像这样

    <?xml version="1.0" encoding="utf-8"?>
<xsl:stylesheet version="1.0" xmlns:xsl="http://www.w3.org/1999/XSL/Transform"
    xmlns:msxsl="urn:schemas-microsoft-com:xslt" exclude-result-prefixes="msxsl">
    <xsl:output method="xml" indent="yes"/>
  <xsl:key name="FeatureOwner" match="Result" use="@Owner" />
    <xsl:template match="/">
      <html>
        <head>
          <title>Result Summary</title>
        </head>
        <body>
                <table>
                  <tr>
                    <td>
                      <b>Owner</b></td>
                    <td>
                      <b>Total</b>
                    </td>
                    <td>
                      <b>Pass</b>
                    </td>
                    <td>
                      <b>Fail</b>
                    </td>
                  </tr>
                  <xsl:for-each select="ResultCollection/Result[generate-id(.) = generate-id(key('FeatureOwner', @Owner)[1])]">
                    <xsl:variable name="varFeatureOwner">
                      <xsl:value-of select="@Owner" />
                    </xsl:variable>
                    <xsl:variable name="totFailures" select="sum(//ResultCollection/Result[@Owner=$varFeatureOwner]/@Fail)" />
                    <xsl:variable name="totPass" select="sum(//ResultCollection/Result[@Owner=$varFeatureOwner]/@Pass)" />
                    <xsl:variable name="total" select="$totPass+$totFailures" />
                     <tr>
                        <td>
                          <xsl:value-of select="$varFeatureOwner"/>
                        </td>
                        <td>
                          <xsl:value-of select="$total"/>
                        </td>
                        <td>
                          <xsl:value-of select="$totPass"/>
                        </td>
                        <td>
                          <xsl:value-of select="$totFailures"/>
                        </td>
                      </tr>
                  </xsl:for-each>
                </table>
          </body>
      </html>
    </xsl:template>
</xsl:stylesheet>

1 个答案:

答案 0 :(得分:2)

像这样的东西我重新构建了你的代码,因为它缺少了很多):

此XSLT转换

<xsl:stylesheet version="1.0"
 xmlns:xsl="http://www.w3.org/1999/XSL/Transform">

 <xsl:param name="pSortBy" select="'Pass'"/>

 <xsl:key name="kResultByOwner" match="Result"
  use="@Owner"/>

    <xsl:template match="/">
        <table>
            <xsl:for-each select=
            "ResultCollection/Result
                 [generate-id(.) 
                 = 
                  generate-id(key('kResultByOwner', @Owner)[1])
                  ]">
                 <xsl:sort data-type="number" select=
                "sum(key('kResultByOwner', @Owner)
                               /@*[name()=$pSortBy])"/> 

                <xsl:variable name="totFailures" select=
                "sum(/ResultCollection/Result
                          [@Owner=current()/@Owner]
                              /@Fail
               )" />
                <xsl:variable name="totPass" select=
                "sum(/ResultCollection/Result
                           [@Owner=current()/@Owner]
                              /@Pass
               )" />

                <xsl:variable name="total" select=
                   "$totPass+$totFailures" />
                <tr>
                    <td>
                        <xsl:value-of select="current()/@Owner"/>
                    </td>
                    <td>
                        <xsl:value-of select="$total"/>
                    </td>
                    <td>
                        <xsl:value-of select="$totPass"/>
                    </td>
                    <td>
                        <xsl:value-of select="$totFailures"/>
                    </td>
                </tr>
            </xsl:for-each>
        </table>
    </xsl:template>
</xsl:stylesheet>

应用于最初提供的XML文档

<ResultCollection>
    <Result Id="551550" Pass="23" Fail="0" Owner="Dong"/>
    <Result Id="551565" Pass="4" Fail="3" Owner="Dong"/>
    <Result Id="551567" Pass="61" Fail="0" Owner="Mei"/>
    <Result Id="551580" Pass="10" Fail="1" Owner="Dong"/>
    <Result Id="551580" Pass="0" Fail="4" Owner="Sen"/>
    <Result Id="551548" Pass="1" Fail="12" Owner="Sen"/>
</ResultCollection>

产生想要的结果):

Sen        17    1  16
Dong       41   37   4
Mei        61   61   0

请注意以下

  1. 仅属于当前组的元素的@Pass@Fail属性的值的总和(使用key()函数)。< / p>

  2. 使用<xsl:sort .../>指令按所需金额排序。

  3. 使用名为pSortBy的全局参数,其中包含要对其进行排序的属性的名称。

  4. 使用XSLT函数current()