如何在逐个节的查询中使用子查询?
我使用SQL Server 2008 R2和Delphi 2010
我收到此错误:
Cannot perform an aggregate function on an expression
containing an aggregate or a sub query.
喜欢这个查询:
select
t1.sen,
sum(t1.d1)as d1,
sum(t1.d2)as d2,
sum(t1.d1+t1.d2) as d_sum,
Round((sum((1000*(t1.d1+t1.d2))/(9500-(
select sum(t2.t_shab+t2.t_rooz)
from tbl1 t2
where FCode=81 AND DCode=1 AND t2.sen<=t1.sen
)))),1) as SSS
from
tbl1 t1
where
FCode = 81
AND DCode = 1
分组 t1.sen
答案 0 :(得分:2)
没有任何保证,您可以尝试,如果它不起作用,请告诉我,我会删除我的答案
create function getSumBSen(@pfcode number, @pdcode number, @pSen number) returns number
as
begin
declare @r number;
select
@r =sum(t2.t_shab + t2.t_rooz)
from
tbl1 t2
where
t2.FCode = @pfcode
and t2.DCode = @pdcode
and t2.sen <= @pSen
group by t2.FCode, t2.DCode;
return (@r);
end;
select
t1.sen,
sum(t1.d1) as d1,
sum(t1.d2) as d2,
sum(t1.d1 + t1.d2) as d_sum,
Round((sum((1000*(t1.d1+t1.d2))/(9500-getSumBSen(t1.FCode, t1.dcode, t1.sen)))),1) as SSS
from
tbl1 t1
where
t1.FCode = 81
and t1.DCode = 1
group by
t1.sen;
的纪念品:强> 的
补充说,它不会让我实际修复代码,因为我的编辑太短了。所以我不得不写一些杂项垃圾,以便接受代码修复。
答案 1 :(得分:1)
试试这个:
DECLARE @tbl1 AS TABLE
(
FCode INT
,DCode INT
,sen INT
,d1 INT
,d2 INT
,t_shab INT
,t_rooz INT
) ;
SELECT *
FROM (
SELECT t1.sen
,SUM(t1.d1) AS d1
,SUM(t1.d2) AS d2
,SUM(t1.d1 + t1.d2) AS d_sum
,ROUND((SUM((1000 * (t1.d1 + t1.d2)) / (9500 - factor.factor))),
1) AS SSS
FROM @tbl1 AS t1
INNER JOIN (
SELECT t1.sen
,SUM(t2.t_shab + t2.t_rooz) AS factor
FROM @tbl1 AS t2
INNER JOIN @tbl1 AS t1
ON t1.FCode = 81
AND t1.DCode = 1
AND t2.FCode = 81
AND t2.DCode = 1
AND t2.sen <= t1.sen
GROUP BY t1.sen
) AS factor
ON factor.sen = t1.sen
WHERE FCode = 81
AND DCode = 1
GROUP BY t1.sen
) AS X ;
答案 2 :(得分:0)
您应该能够按照以下一般模式将子查询置于FROM
子句下:
SELECT TABLE1.ID, SUM(TABLE1.A), ROUND(SUM(T2.B1), 2)
FROM TABLE1, (SELECT SUM(B) B1 FROM TABLE2 WHERE ...) T2
GROUP BY TABLE1.ID
尝试“翻译”您的查询,您可能会得到类似的内容:
select
t1.sen,
sum(t1.d1)as d1,
sum(t1.d2)as d2,
sum(t1.d1+t1.d2) as d_sum,
Round((sum((1000*(t1.d1+t1.d2))/(9500-(
t2a.s
)))),1) as SSS
from
tbl1 t1,
(
select sum(t2.t_shab+t2.t_rooz) s
from tbl1 t2
where FCode=81 AND DCode=1 AND t2.sen<=t1.sen
) t2a
where
FCode = 81
AND DCode = 1
group by
t1.sen
答案 3 :(得分:0)
它的真实方式
create function getSumBSen2(@pfcode INT, @pdcode INT, @pSen INT) returns int
as
begin
declare @r int;
select
@r= sum(t2.t_shab + t2.t_rooz)
from
tbl1 t2
where
t2.FCode = @pfcode
and t2.DCode = @pdcode
and t2.sen <= @pSen;
return (@r);
end;
GO
select
t1.sen,
sum(t1.d1) as d1,
sum(t1.d2) as d2,
sum(t1.d1 + t1.d2) as d_sum,
Round((sum((1000*(t1.d1+t1.d2)+0.01)/(9500-(dbo.getSumBSen2(t1.FCode, t1.DCode, t1.sen))))),1) as SSS
from
tbl1 t1
where
t1.FCode = 81
and t1.DCode = 1
group by
t1.sen;