以下代码用于旋转图像并调整其大小,
<?php
$src = "41611326.png";
// Get new dimensions
list($width, $height) = getimagesize($src);
$new_width = 192;
$new_height = 192;
$dstimage=imagecreatetruecolor($new_width,$new_height);
$srcimage = imagecreatefrompng($src);
$degrees = -30;
$srcimage = imagerotate($srcimage, $degrees, 0) ;
imagealphablending($dstimage, false);
imagesavealpha($dstimage, true);
imagecopyresampled($dstimage,$srcimage,0,0,0,0, $new_width,$new_height,$width,$height);
header('Content-type: image/png') ;
imagepng($dstimage) ;
?>
但它没有获得输出图像的透明背景。如何保持透明背景。
请帮助
答案 0 :(得分:1)
function rotate_transparent_img( $img_resource, $angle ){
$pngTransparency = imagecolorallocatealpha( $img_resource , 0, 0, 0, 127 );
imagefill( $img_resource , 0, 0, $pngTransparency );
$result = imagerotate( $img_resource, $angle, $pngTransparency );
imagealphablending( $result, true );
imagesavealpha( $result, true );
return $result;
}
<强>用法:强>
$img_resource = imagecreatefrompng('transparent_img.png');
$angle = 30;
$res = rotate_transparent_img( $img_resource, $angle );
header('Content-Type: image/png');
imagepng($res);
答案 1 :(得分:0)
我认为你需要使用imagecolortransparent()函数。
答案 2 :(得分:0)
改变:
$srcimage = imagerotate($srcimage, $degrees, 0) ;
到:
$srcimage = imagerotate($srcimage, $degrees, -1);