Question

我有一个数组

$rules = array(
    'name' => array(
        'isRequired' => array(
            'message' => 'Name Required'
         ),
        'isBetween' => array(
              'value' => array(5,15),
              'message' => 'Between 5 to 15 characters'
        ),
        'isAlphaLower' => array(
            'message' => 'Should be Alpha lower'
        ),
        'isLength' => array(
            'value' => 20,
            'message' => 'Length should be 20 chracters'
        )
    ),
    'email' => array(
        'isEmail' => array(
            'message' => 'Email should be valid'
        ),
        'isRequired' => array(
            'message' => 'Email Required'
        ),
    ),
    'pPhone' => array(
        'isNumber' => array(
            'message' => 'Only Numbers'
        )
    )
);

我需要删除键名为message的所有数组元素。我该怎么做？

谢谢..

Answer 1

嵌套的foreach，参考。

foreach( $rules as $field => &$fieldrules ) {
    foreach( $fieldrules as $rulename => &$rulesettings ) {
        unset( $rulesettings['message'] );
    }
}

Answer 2

如果您要删除密钥为'message'三个级别的所有键/值对，您可以尝试以下操作：

foreach ($rules as $k1 => $arr) {
    foreach ($arr as $k2 => $arr2) {
        foreach ($arr2 as $k3 => $arr3) {
            if ($k3 == 'message') {
                unset($rules[$k1][$k2][$k3]);
            }
        }
    }
}

Answer 3

在嵌套unset()中使用foreach loop：

foreach($rules as &$fieldrules)
  foreach($fieldrules as &$ruleparams)
    if(isset($ruleparams['message'])) // E_STRICT
      unset($ruleparams['message']);

注意变量前的&。这是一个参考传递。这样做很重要，这样我们就可以修改实际的数组，而不是副本。

如何在PHP中删除多个数组元素？

3 个答案: