如何以秒为单位获取当前UTC时间

时间:2011-09-28 00:27:33

标签: java time seconds

我有一个应用程序,需要以秒为单位比较时间。

我想知道如何以秒为单位获取当前的UTC时间。

有人可以发布一个例子吗?我们怎样才能在Java中做到这一点?

7 个答案:

答案 0 :(得分:16)

您可以使用它来获取您想要时间的时区传递时区

Calendar cal = Calendar.getInstance(TimeZone.getTimeZone("UTC")); 

然后你可以在日历对象上调用你想要的任何东西

System.out.println(cal.get(Calendar.YEAR));
System.out.println(cal.get(Calendar.HOUR));
System.out.println(cal.get(Calendar.HOUR_OF_DAY));
System.out.println(cal.get(Calendar.MINUTE));

以下示例以秒为单位比较两个日历

Calendar cal1 = Calendar.getInstance(TimeZone.getTimeZone("UTC"));
Calendar cal2 = Calendar.getInstance(TimeZone.getTimeZone("UTC"));

// Set the dates for calendars
cal1.set(2011, 1, 1);
cal2.set(2011, 2, 2);

// Get the represented date in milliseconds as a long
long milis1 = cal1.getTimeInMillis();
long milis2 = cal2.getTimeInMillis();

// Calculate difference in milliseconds
long diff = milis2 - milis1;

// Calculate difference in seconds
long diffSecs = diff / 1000;

System.out.println("In seconds: " + diffSecs + " seconds");

答案 1 :(得分:11)

答案 2 :(得分:3)

Joda简化了一切

import org.joda.time.ReadableInstant;
import org.joda.time.DateTime;

import static org.joda.time.DateTimeZone.UTC;
import static org.joda.time.Seconds.secondsBetween;

...

ReadableInstant start = new DateTime("2011-01-01", UTC);
ReadableInstant end = new DateTime("2011-02-02", UTC);

int secondsDifference = secondsBetween(start, end).getSeconds();

答案 3 :(得分:2)

 public static  long getUtcTime(long time) {
    System.out.println("Time="+time);
     SimpleDateFormat format=new SimpleDateFormat("yyyy-MM-dd HH:mm:ss.SSS");
       Date dbefore=new Date(time);
       System.out.println("Date before conversion="+format.format(dbefore));
      Calendar c = Calendar.getInstance();
       c.setTimeInMillis(time);
          TimeZone timezone = c.getTimeZone();
        int offset = timezone.getRawOffset();
        if(timezone.inDaylightTime(new Date())){
            offset = offset + timezone.getDSTSavings();
        }
        int offsetHrs = offset / 1000 / 60 / 60;
        int offsetMins = offset / 1000 / 60 % 60;

        System.out.println("offset: " + offsetHrs);
        System.out.println("offset: " + offsetMins);

        c.add(Calendar.HOUR_OF_DAY, (-offsetHrs));
        c.add(Calendar.MINUTE, (-offsetMins));

        System.out.println("Date after conversion: "+format.format(c.getTime()));
      System.out.println("Time converted="+c.getTime().getTime());
         return c.getTime().getTime();


    }

答案 4 :(得分:1)

以秒为单位获取当前UTC时间(自1.5起):

TimeUnit.MILLISECONDS.toSeconds(System.currentTimeMillis())

根据Javadoc:

  

http://docs.oracle.com/javase/1.4.2/docs/api/java/lang/System.html#currentTimeMillis

     

返回:

     

当前时间与之间的差异,以毫秒为单位   UTC时间1970年1月1日午夜。

答案 5 :(得分:0)

要将日期存储为整数而不是长整数,可以除以1000,还可以选择除以另一个日期,例如2019年1月1日:

private int getUTC()
{
    Calendar cal1 = Calendar.getInstance(TimeZone.getTimeZone("UTC"));
    cal1.set(2019, 1, 1);
    long millis1 = cal1.getTimeInMillis();

    //Current date in milliseconds
    long millis2 = TimeUnit.MILLISECONDS.toSeconds(System.currentTimeMillis());

    // Calculate difference in seconds
    long diff = millis2 - millis1;
    return (int)(diff / 1000);
}

答案 6 :(得分:-1)

这有效:

    Calendar calendar = Calendar.getInstance(TimeZone.getTimeZone("UTC"));
    GregorianCalendar gregorianCalendar = new GregorianCalendar
    (
        calendar.get(Calendar.YEAR),
        calendar.get(Calendar.MONTH),
        calendar.get(Calendar.DAY_OF_MONTH),
        calendar.get(Calendar.HOUR_OF_DAY),
        calendar.get(Calendar.MINUTE),
        calendar.get(Calendar.SECOND)
    );
    return gregorianCalendar.getTime();