Question

我知道在HtmlUnit中我可以fireEvent在表单上提交，然后发布。但是如果我禁用了javascript并希望使用一些内置函数发布表单？

我已经检查了javadoc并且没有找到任何方法来执行此操作。很奇怪HtmlForm中没有这样的功能......

我在htmlunit页面上阅读了javadoc和教程，我知道我可以使用getInputByName()并单击它。 BuT有时会有没有提交类型按钮的表单甚至有这样的按钮但没有名字属性。

我在这种情况下寻求帮助，这就是我使用fireEvent的原因，但它并不总是有效。

Answer 1

您可以使用“临时”提交按钮：

WebClient client = new WebClient();
HtmlPage page = client.getPage("http://stackoverflow.com");

// create a submit button - it doesn't work with 'input'
HtmlElement button = page.createElement("button");
button.setAttribute("type", "submit");

// append the button to the form
HtmlElement form = ...;
form.appendChild(button);

// submit the form
page = button.click();

Answer 2

WebRequest requestSettings = new WebRequest(new URL("http://localhost:8080/TestBox"), HttpMethod.POST);

// Then we set the request parameters
requestSettings.setRequestParameters(Collections.singletonList(new NameValuePair(InopticsNfcBoxPage.MESSAGE, Utils.marshalXml(inoptics, "UTF-8"))));

// Finally, we can get the page
HtmlPage page = webClient.getPage(requestSettings);

Answer 3

final HtmlSubmitInput button = form.getInputByName("submitbutton");
final HtmlPage page2 = button.click()

来自the htmlunit doc

@Test
public void submittingForm() throws Exception {
    final WebClient webClient = new WebClient();

    // Get the first page
    final HtmlPage page1 = webClient.getPage("http://some_url");

    // Get the form that we are dealing with and within that form, 
    // find the submit button and the field that we want to change.
    final HtmlForm form = page1.getFormByName("myform");

    final HtmlSubmitInput button = form.getInputByName("submitbutton");
    final HtmlTextInput textField = form.getInputByName("userid");

    // Change the value of the text field
    textField.setValueAttribute("root");

    // Now submit the form by clicking the button and get back the second page.
    final HtmlPage page2 = button.click();

    webClient.closeAllWindows();
}

Answer 4

如何使用内置的javascript支持？只需在该表单上触发提交事件：

HtmlForm form = page.getForms().get(0);
form.fireEvent(Event.TYPE_SUBMIT);

代码假设您要在网站上提交第一个表单。

如果提交转发到另一个网站，只需将响应链接到页面变量：

HtmlForm form = page.getForms().get(0);
page = (HtmlPage) form.fireEvent(Event.TYPE_SUBMIT).getNewPage();

HtmlUnit，如何在不单击提交按钮的情况下发布表单？

4 个答案: