我有两张桌子。一个是newBus,第二个是newPassengers。表newBus包含列startcity和endCity。现在让我们说newBus.startCity包含:
newBus.id----newBus.startCity-----newBus.endCity
4 ACity to xCity
5 tCity to MCity
newPassenger表: 3名乘客想去
newPassengers.s_city------newPassengers.e_city
tCity to GCity
OCity to FCity
tCity to MCity
我想选择所有想要从tCity到MCity但是相对于newBus.id = 5的乘客。
答案 0 :(得分:1)
SELECT newPassengers.id
FROM newBus
INNER JOIN newPassengers ON newPassengers.s_city = newBus.startCity
WHERE newPassengers.s_city = 'tCity'
AND newPassengers.e_city = 'MCity'
AND newBus.id = 5
这假设所有乘客都会乘坐与起始城市相同的起始城市的公交车,并且乘客的ID是newPassengers.id。您可以在选择列表中添加更多字段以获取您所需的信息。
答案 1 :(得分:0)
我想选择所有想要从tCity到MCity但是相对于newBus.id = 5的乘客。
SELECT p.id
FROM newpassengers p
INNER JOIN newbus b ON (p.s_city = b.startcity AND p.e_city = b.endCity)
WHERE p.s_city = 'tCity' AND p.e_city = 'MCity' AND b.id = '5';