如何将通用参数传递给多个委托。 2具有通用参数的代表

时间:2011-09-27 11:50:41

标签: c# delegates

我有一个接受两个delegate s作为参数的方法。

method1(Delegate delegate1,Delegate delegate2,params Object[] parameters)
{
    // There is lot of other code, I haven't put here. To make it clear.
    string key = delegate1.DynamicInvoke(parameters);
    object instance = delegate2.DynamicInvoke(parameters); 
    // Getting errors here, as parameters mismatch.
}

// Code from the Calling class
// There are many other classes in my project, which are calling Method1, 
// but the number of parameters of method2 and method3 always vary. 
private string Method2(object[] paramsObject)
{
    string key = string.Empty;
    foreach (object obj in paramsObject)
    {
        key += obj.ToString() + "|";
    }
    return key.Trim(new char[]{'|'});
}

private object Method3(object[] paramsObject)
{
    object object1 = paramsObject[0];
    object object2 = paramsObject[1];
    object object3 = paramsObject[2];
    object object4 = GetObjectUsingParameters(object1,object2,object3);
    return object4;
}


Func<string, string, string> Method2Delegate = Method2;
Func<object1,object2,object3,object4> Method3Delegate = Method3;
//Calling Method1
Method1(Method2Delegate,Method3Delegate,string str1,string str2,object object1,Object object2,Object object3);

我在Method1调用delegate s参数不匹配错误时收到错误。

因为我们最后只能有一个params参数作为方法的输入。

您能否告诉我,如何将参数绑定到同一delegate或如何解决此问题?

非常感谢。

2 个答案:

答案 0 :(得分:0)

您需要使用下一个签名创建委托:

delegate void MyCustomDelegate (params object[] params);

然后将Method2Delegate和Method3Delegate定义为MyCustomDelegate类型。

答案 1 :(得分:0)

这样做是怎么回事:

method1(Func<object[],string> delegate1,Func<object[], object> delegate2,params Object[] parameters)
{

// There is lot of other code, I haven't put here. To make it clear.

    string key = delegate1(parameters);

    object instance = delegate2(parameters); 
// Getting errors here, as parameters mismatch. 

}

并且在来电者处

Method1(Method2,Method3,string str1,string str2,object object1,Object object2,Object object3);

这样您就不需要定义动态调用的委托。