PostgreSQL函数返回多个结果集

Question

是否可以从Postgres函数返回多个结果集，如在MSSQL中：

CREATE PROCEDURE test

AS

SELECT * FROM first_table

SELECT * FROM second_table

Answer 1

自PostgreSQL 8.3 后，一种更简单的方法就是：

CREATE FUNCTION test()
  RETURNS SETOF first_table AS
$func$
BEGIN

RETURN QUERY
SELECT * FROM first_table;

RETURN QUERY
SELECT * FROM second_table;   -- has to return same rowtype as first_table!

END
$func$ LANGUAGE plpgsql;

呼叫：

SELECT * FROM test();

两个结果集都附加到从函数返回的单个集合中 请参阅manual for RETURN QUERY。

Answer 2

CREATE OR REPLACE FUNCTION "pr_GetCustomersAndOrders"()
RETURNS SETOF refcursor AS
$BODY$DECLARE
customerRC refcursor;
orderRC refcursor;
BEGIN
open customerRC FOR
SELECT * FROM customers;
RETURN NEXT customerRC;

open orderRC FOR
SELECT * FROM orders;
RETURN NEXT orderRC;
RETURN;
END;$BODY$
LANGUAGE 'plpgsql' VOLATILE;
ALTER FUNCTION "pr_GetCustomersAndOrders"() OWNER TO postgres;

I.o.w。使用refcursors：）

Answer 3

如果first_table和second_table具有相同的布局，您也可以使用

SELECT * FROM first_table WHERE ...
UNION ALL
SELECT * FROM second_table WHERE ...

[编辑：感谢评论者（其名称可能不是“null”:)）指出UNION ALL比UNION更快。]

Answer 4

CREATE OR REPLACE FUNCTION public.TestReturnMultipleTales
( 
 param_coid integer, 
 ref1 refcursor,
 ref2 refcursor
)
RETURNS SETOF refcursor 
LANGUAGE 'plpgsql'
COST 100
VOLATILE PARALLEL UNSAFE
ROWS 1000

AS $BODY$
DECLARE
            
BEGIN
  OPEN ref1 FOR SELECT * FROM dbo.tbl1 WHERE coid = param_coid;
  RETURN NEXT ref1;

  OPEN ref2 FOR SELECT * FROM dbo.tbl2 LIMIT 5;
  RETURN NEXT ref2;
END;
$BODY$;

USE IN pgSQL Query:- 

BEGIN;
    SELECT football_players.show_cities_multiple(123456, 'Ref1', 'Ref2');
    FETCH ALL IN "Ref1";
    FETCH ALL IN "Ref2";
COMMIT;

SELECT football_players.show_cities_multiple(123456, 'Ref1', 'Ref2');
FETCH ALL IN "Ref1";

SELECT football_players.show_cities_multiple(123456, 'Ref1', 'Ref2');
FETCH ALL IN "Ref2";

Answer 5

是

示例：

test=# create function x () returns setof integer language plpgsql as $$ begin return next 1; return next 2; end $$;
CREATE FUNCTION
test=# select * from x();
 x 
---
 1
 2
(2 rows)

您当然可以使用现有的表/视图或返回类型的自定义类型。

使用语言SQL的示例：

test=# create table customer (name varchar, birth_date date);
CREATE TABLE
test=# create function y () returns setof customer language sql as $$ 
select * from customer
union all
select * from customer
$$;
CREATE FUNCTION
test=# insert into customer values ('joe', now()::date);
INSERT 0 1
test=# insert into customer values ('jill', now()::date);
INSERT 0 1
test=# select * from y();
 name | birth_date 
------+------------
 joe  | 2009-04-16
 jill | 2009-04-16
 joe  | 2009-04-16
 jill | 2009-04-16
(4 rows)

See here for doc