Question

我有这个SQL（对于MySQL）：

create table apartmentcaretakers
(
apartmentID int,
caretakerID int,
PRIMARY KEY (apartmentID, caretakerID),
FOREIGN KEY (apartmentID) REFERENCES apartments(apartmentID),
FOREIGN KEY (caretakerID) REFERENCES caretakers(caretakerID)
)engine = innodb;

我的错误： 'references apartments（apartmentID）附近的SQL语法错误，外键caretakerID引用看护人'

这对我来说是一个小错误，但有人可以指出吗？

编辑：经过一些编码和重新运行后，错误是1064.我可以理解为什么它没有真正帮助，因为这是一个广谱错误。

Answer 1

也为我工作。

确保您引用的表也使用INNODB引擎。使用以下查询检查：SHOW TABLE STATUS WHERE Name = 'xxx'

mysql> CREATE TABLE apartments (
    -> apartmentID int PRIMARY KEY NOT NULL) ENGINE = innodb;
Query OK, 0 rows affected (0.01 sec)

mysql> CREATE TABLE caretakers (
    -> caretakerID int PRIMARY KEY NOT NULL) ENGINE = innodb;
Query OK, 0 rows affected (0.02 sec)

mysql> CREATE TABLE apartmentcaretakers (
    -> apartmentID int,
    -> caretakerID int,
    -> PRIMARY KEY (apartmentID, caretakerID),
    -> FOREIGN KEY ac_fk_apartments_id (apartmentID) REFERENCES apartments (apartmentID),
    -> FOREIGN KEY ac_fk_caretakers_id(caretakerID) REFERENCES caretakers (caretakerID)
    -> ) ENGINE = innodb;

Query OK, 0 rows affected (0.02 sec)

N：M关系语法代码错误

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