我有这个不编译的代码:
public struct MyStruct
{
private fixed uint myUints[32];
public uint[] MyUints
{
get
{
return this.myUints;
}
set
{
this.myUints = value;
}
}
}
现在,我知道为什么代码无法编译,但我显然已经太累了无法思考,需要一些帮助才能让我朝着正确的方向前进。我有一段时间没有处理不安全的代码,但我很确定我需要做一个Array.Copy
(或Buffer.BlockCopy
?)并返回一个数组的副本,但是那些不是采取我需要的论据。我忘记了什么?
感谢。
答案 0 :(得分:5)
使用fixed
缓冲区时,您必须在fixed
上下文中工作:
public unsafe struct MyStruct {
private fixed uint myUints[32];
public uint[] MyUints {
get {
uint[] array = new uint[32];
fixed (uint* p = myUints) {
for (int i = 0; i < 32; i++) {
array[i] = p[i];
}
}
return array;
}
set {
fixed (uint* p = myUints) {
for (int i = 0; i < 32; i++) {
p[i] = value[i];
}
}
}
}
}
答案 1 :(得分:2)
可能有一个更简单的解决方案,但这有效:
public unsafe struct MyStruct
{
private fixed uint myUints[32];
public uint[] MyUints
{
get
{
fixed (uint* ptr = myUints)
{
uint[] result = new uint[32];
for (int i = 0; i < result.Length; i++)
result[i] = ptr[i];
return result;
}
}
set
{
// TODO: make sure value's length is 32
fixed (uint* ptr = myUints)
{
for (int i = 0; i < value.Length; i++)
ptr[i] = value[i];
}
}
}
}
答案 2 :(得分:0)
这仅适用于int
,float
,byte
,char
和double
,但您可以使用Marshal.Copy()
来移动数据固定数组到托管数组。
示例:
class Program
{
static void Main(string[] args)
{
MyStruct s = new MyStruct();
s.MyUints = new int[] {
1, 2, 3, 4, 5, 6, 7, 8,
9, 10, 11, 12, 13, 14, 15, 16,
1, 2, 3, 4, 5, 6, 7, 8,
9, 10, 11, 12, 13, 14, 15, 16 };
int[] chk = s.MyUints;
// chk containts the proper values
}
}
public unsafe struct MyStruct
{
public const int Count = 32; //array size const
fixed int myUints[Count];
public int[] MyUints
{
get
{
int[] res = new int[Count];
fixed (int* ptr = myUints)
{
Marshal.Copy(new IntPtr(ptr), res, 0, Count);
}
return res;
}
set
{
fixed (int* ptr = myUints)
{
Marshal.Copy(value, 0, new IntPtr(ptr), Count);
}
}
}
}