Question

我有以下代码从手机向服务器发送文件（mpeg文件 - 大约20kb）。但是，它在服务器端失败了。任何人都可以告诉我我在客户端犯的错误是什么？感谢。

ByteArrayOutputStream bos = new ByteArrayOutputStream();
        //bm.compress(CompressFormat.JPEG, 75, bos);
        byte[] data = bos.toByteArray();
        HttpClient httpClient = new DefaultHttpClient();
        HttpPost postRequest = new HttpPost("http://example.com/upload.php");
        File file= new File("/mnt/sdcard/enca/aha.mpeg");
        FileBody bin = new FileBody(file);
        MultipartEntity reqEntity = new     MultipartEntity(HttpMultipartMode.BROWSER_COMPATIBLE);
        reqEntity.addPart("uploaded", bin);
        reqEntity.addPart("random", new StringBody(encameo1.random));
        reqEntity.addPart("fingerPrint", new StringBody(encameo1.fingerprint));
        postRequest.setEntity(reqEntity);
        HttpResponse response = httpClient.execute(postRequest);
        BufferedReader reader = new BufferedReader(new InputStreamReader(response.getEntity().getContent(), "UTF-8"));
        String sResponse;
        StringBuilder s = new StringBuilder();

        while ((sResponse = reader.readLine()) != null) {
            s = s.append(sResponse);
        }
        System.out.println("Response: " + s);

php代码：

<?php



$target_path = "uploaded_files/";

$target_path = $target_path . basename( $_FILES['userfile']['name']); 

if(move_uploaded_file($_FILES['userfile']['tmp_name'], $target_path)) 
{

    echo "The file ".  basename( $_FILES['userfile']['name'])." has been uploaded";

} 

else
{

    echo "There was an error uploading the file, please try again!";

}



?>

Answer 1

您正在发送名为uploaded的部分：

reqEntity.addPart("uploaded", bin);

但是，PHP期望名为userfile的部分：

if(move_uploaded_file($_FILES['userfile']['tmp_name'], $target_path))

将它对齐。

使用multipart从Android上传文件的问题

1 个答案: