Question

基本上我有以下查询：

SELECT DISTINCT users.ID, users.name
FROM users 
INNER JOIN usersSkills ON users.ID = usersSkills.userID 
INNER JOIN usersLanguages ON users.ID = usersLanguages.userID 
WHERE activated = "1" 
AND type = "GRADUATE" 
AND usersSkills.skillID IN(2, 21)
AND usersLanguages.languageID IN(2, 22)

我需要将技能ID和languageID与IN（）函数中传递的每个参数匹配，如果找到任一参数，它将在每个参数上提供结果。

所以基本上我只想在技能表上找到2和21的技能ID以及语言的相同想法时才能看到结果......

Answer 1

使用GROUP BY（这也不需要SELECT DISTINCT）来获取聚合计数和HAVING子句，以确保返回的不同元素的数量与您要搜索的元素数量相匹配。

SELECT users.ID, users.name
FROM users 
INNER JOIN usersSkills ON users.ID = usersSkills.userID 
INNER JOIN usersLanguages ON users.ID = usersLanguages.userID 
WHERE activated = "1" 
AND type = "GRADUATE" 
AND usersSkills.skillID IN(2, 21)
AND usersLanguages.languageID IN(2, 22)
GROUP BY users.ID, users.name
HAVING COUNT(DISTINCT usersSkills.skillID) = 2
   AND COUNT(DISTINCT usersLanguages.languageID) = 2

匹配MYSQL IN（）中传递的每个变量

1 个答案: