Question

我正试图制作这个正则表达式：

var url_pattern = /(\()((?:ht|f)tps?:\/\/[a-z0-9\-._~!$&'()*+,;=:\/?#[\]@%]+)(\))|(\[)((?:ht|f)tps?:\/\/[a-z0-9\-._~!$&'()*+,;=:\/?#[\]@%]+)(\])|(\{)((?:ht|f)tps?:\/\/[a-z0-9\-._~!$&'()*+,;=:\/?#[\]@%]+)(\})|(<|&(?:lt|#60|#x3c);)((?:ht|f)tps?:\/\/[a-z0-9\-._~!$&'()*+,;=:\/?#[\]@%]+)(>|&(?:gt|#62|#x3e);)|((?:^|[^=\s'"\]])\s*['"]?|[^=\s]\s+)(\b(?:ht|f)tps?:\/\/[a-z0-9\-._~!$'()*+,;=:\/?#[\]@%]+(?:(?!&(?:gt|#0*62|#x0*3e);|&(?:amp|apos|quot|#0*3[49]|#x0*2[27]);[.!&',:?;]?(?:[^a-z0-9\-._~!$&'()*+,;=:\/?#[\]@%]|$))&[a-z0-9\-._~!$'()*+,;=:\/?#[\]@%]*)*[a-z0-9\-_~$()*+=\/#[\]@%])/img;

符合JSLint标准。它抱怨使用。而不是逃避[和]。

（资料来源：http://jmrware.com/articles/2010/linkifyurl/linkify.html）

编辑：不是那么大的交易，我只是在后端做了。我还是喜欢一个版本（因为我正在构建一个渲染引擎，但这不再是紧急的了。）

Answer 1

替换：

var url_pattern = /(\()((?:ht|f)tps?:\/\/[a-z0-9\-._~!$&'()*+,;=:\/?#[\]@%]+)(\))|(\[)((?:ht|f)tps?:\/\/[a-z0-9\-._~!$&'()*+,;=:\/?#[\]@%]+)(\])|(\{)((?:ht|f)tps?:\/\/[a-z0-9\-._~!$&'()*+,;=:\/?#[\]@%]+)(\})|(<|&(?:lt|#60|#x3c);)((?:ht|f)tps?:\/\/[a-z0-9\-._~!$&'()*+,;=:\/?#[\]@%]+)(>|&(?:gt|#62|#x3e);)|((?:^|[^=\s'"\]])\s*['"]?|[^=\s]\s+)(\b(?:ht|f)tps?:\/\/[a-z0-9\-._~!$'()*+,;=:\/?#[\]@%]+(?:(?!&(?:gt|#0*62|#x0*3e);|&(?:amp|apos|quot|#0*3[49]|#x0*2[27]);[.!&',:?;]?(?:[^a-z0-9\-._~!$&'()*+,;=:\/?#[\]@%]|$))&[a-z0-9\-._~!$'()*+,;=:\/?#[\]@%]*)*[a-z0-9\-_~$()*+=\/#[\]@%])/img;

带

var url_pattern = new RegExp("([\\.+])", "img"); // simplified for my sanity

正确转义字符串，\至\\

编辑：

var a = new RegExp("(\\()((?:ht|f)tps?:\\/\\/[a-z0-9\\-._~!$&'()*+,;=:\\/?#[\\]@%]+)(\\))|(\\[)((?:ht|f)tps?:\\/\\/[a-z0-9\\-._~!$&'()*+,;=:\\/?#[\\]@%]+)(\\])|(\\{)((?:ht|f)tps?:\\/\\/[a-z0-9\\-._~!$&'()*+,;=:\\/?#[\\]@%]+)(\\})|(<|&(?:lt|#60|#x3c);)((?:ht|f)tps?:\\/\\/[a-z0-9\\-._~!$&'()*+,;=:\\/?#[\\]@%]+)(>|&(?:gt|#62|#x3e);)|((?:^|[^=\\s'\"\\]])\\s*['\"]?|[^=\\s]\\s+)(\\b(?:ht|f)tps?:\\/\\/[a-z0-9\\-._~!$'()*+,;=:\\/?#[\\]@%]+(?:(?!&(?:gt|#0*62|#x0*3e);|&(?:amp|apos|quot|#0*3[49]|#x0*2[27]);[.!&',:?;]?(?:[^a-z0-9\\-._~!$&'()*+,;=:\\/?#[\\]@%]|$))&[a-z0-9\\-._~!$'()*+,;=:\\/?#[\\]@%]*)*[a-z0-9\\-_~$()*+=\\/#[\\]@%])", "gim");

以上传递jslint

Answer 2

以下是包含转义[字符的版本： var url_pattern = /($)((?:ht|f)tps?:\/\/[a-z0-9\-._~!$&'()*+,;=:\/?#\[\]@%]+)($)|(\[)((?:ht|f)tps?:\/\/[a-z0-9\-._~!$&'()*+,;=:\/?#\[\]@%]+)(\])|(\{)((?:ht|f)tps?:\/\/[a-z0-9\-._~!$&'()*+,;=:\/?#\[\]@%]+)(\})|(<|&(?:lt|#60|#x3c);)((?:ht|f)tps?:\/\/[a-z0-9\-._~!$&'()*+,;=:\/?#\[\]@%]+)(>|&(?:gt|#62|#x3e);)|((?:^|[^=\s'"\]])\s*['"]?|[^=\s]\s+)(\b(?:ht|f)tps?:\/\/[a-z0-9\-._~!$'()*+,;=:\/?#\[\]@%]+(?:(?!&(?:gt|#0*62|#x0*3e);|&(?:amp|apos|quot|#0*3[49]|#x0*2[27]);[.!&',:?;]?(?:[^a-z0-9\-._~!$&'()*+,;=:\/?#\[\]@%]|$))&[a-z0-9\-._~!$'()*+,;=:\/?#\[\]@%]*)*[a-z0-9\-_~$()*+=\/#\[\]@%])/img;

它仍然抱怨“不安全的^”，这很难解决，因为它基本上暗示你应该写出你想要匹配的所有字符而不是列出你的那些不想匹配。这当然违背了^的目的。所以你可以忽略这个警告。

试图使正则表达式JSLint兼容

2 个答案: