Question

我在字符串中有一些数据格式为key：value key：value key：value etc ...

我正在尝试使用正则表达式匹配将其转换为数组。键都是大写字母，后面跟冒号。然后有一个空格，值开始。然后是空格，然后是下一个键。该值可以包含大写/小写字母，数字，空格，逗号或等号。

例如，我想要这个输入字符串：

NAME: Name of Item COLOR: green SIZE: 40

变成了这个数组：

newArray[NAME] = Name of Item
newArray[COLOR] = green
newArray[SIZE] = 40

非常感谢任何帮助。此外，我无法访问输入的格式，或者我会让自己更轻松。

Answer 1

通用解决方案：

$str = 'NAME: Name of Item COLOR: green SIZE: 40';

$split = preg_split('/([A-Z]+):/', $str, -1,
            PREG_SPLIT_DELIM_CAPTURE | PREG_SPLIT_NO_EMPTY);

echo 'Split Array is: ' . var_export($split, true);

$newArray = array();

// Stick the key and value together (processing two entries at a time.
for ($i = 0; $i < count($split) - 1; $i = $i + 2)
{
   $newArray[$split[$i]] = trim($split[$i + 1]); // Probably trim them.
}

echo 'New Array is: ' . var_export($newArray, true);

Answer 2

这有效：

$text = "NAME: Name of Item COLOR: green SIZE: 40";
if (preg_match('/NAME: (.+) COLOR: (.+) SIZE: (\d+)/i', $text, $matches))
{
    //var_dump($matches);
    $newArray = array();
    $newArray['NAME'] = $matches[1];
    $newArray['COLOR'] = $matches[2];
    $newArray['SIZE'] = $matches[3];
    var_dump($newArray);
}
else
    echo "No matches";

Answer 3

我建议

$str = "NAME: Name of Item COLOR: green SIZE: 40";

preg_match_all('~([A-Z]+):(.+?)(?=[A-Z]+:|$)~', $str, $m, PREG_SET_ORDER);
foreach($m as $e)
    $result[$e[1]] = trim($e[2]);

print_r($result);

PHP正则表达式匹配麻烦

3 个答案: