没有得到Android应用程序中的url响应

Question

我正在开发一个Android应用程序，其中我在listview中有5个项目。我无法在列表视图中获取我的数据，...我已经尝试了所有的东西,,,但是在listview中没有任何东西

我的网址是

http://harpreetvir.web708.discountasp.net/PMevents/XmlRecord/AddEvent.xml

我的ddms logcat是http://pastebin.com/YH0JWiRJ

有人可以帮忙吗？

Answer 1

请仔细阅读以下代码。

      try {
           HttpClient client = new DefaultHttpClient();  
           String postURL = "http://harpreetvir.web708.discountasp.net/PMevents/XmlRecord/AddEvent.xml";
           HttpGet post = new HttpGet(postURL);
           HttpResponse responsePOST = client.execute(post);  
           HttpEntity resEntity = responsePOST.getEntity();  
           String str1=EntityUtils.toString(resEntity);
           str1=str1.trim();
           parsing(str1);
      } 
      catch (XmlPullParserException e) {
         e.printStackTrace();
      } catch (IOException e) {
         e.printStackTrace();
      }
      public void parsing(String str1) throws XmlPullParserException, IOException{
        XmlPullParserFactory factory = XmlPullParserFactory.newInstance();
        factory.setNamespaceAware(true);
        XmlPullParser xpp = factory.newPullParser();
        xpp.setInput( new StringReader (str1));
        int eventType = xpp.getEventType();
        while (eventType != XmlPullParser.END_DOCUMENT) {
         String str;
         if(eventType == XmlPullParser.START_DOCUMENT) {
            System.out.println("Start document");
         } else if(eventType == XmlPullParser.START_TAG) {
             str    =   xpp.getName();
             System.out.println("Start tag "+str);

         } else if(eventType == XmlPullParser.END_TAG) {
             System.out.println("End tag "+xpp.getName());
         } else if(eventType == XmlPullParser.TEXT) {
             System.out.println("Value= "+xpp.getText());
         }
         eventType = xpp.next();
        }
       System.out.println("End document");
    }