android:ksoap2 org.xmlpull.v1.XmlPullParserException:expected:START_TAG exception

时间:2011-09-26 02:18:29

标签: android exception ksoap2

我正在尝试从网络服务获得回复。但是我收到了一些异常错误:主要是这个

org.xmlpull.v1.XmlPullParserException: expected: START_TAG {http://schemas.xmlsoap.org/soap/envelope/}Envelope (position:START_TAG <html>@1:6 in java.io.InputStreamReader@40524b78) 

实际上我正在尝试访问Web服务的方法,而webservice应该返回两个字符串(比如说String1和String2)。此外,我必须提供或传递两个参数(比如参数1和参数2,其中参数1应该是整数,参数2应该是字符串)这是我的代码

public class MyWebService extends Activity {

private static final String SOAP_ACTION ="http://www.mywebsite.com/myMethod";
private static final String METHOD_NAME = "MyMethod";
private static final String NAMESPACE = "http://www.myNamespace/";
    private static final String URL = "http://mysession.com/myservice.asmx?WSDL";


@Override
public void onCreate(Bundle savedInstanceState) {
    super.onCreate(savedInstanceState);
    setContentView(R.layout.main);

    try {
        SoapObject request = new SoapObject(NAMESPACE, METHOD_NAME);

        PropertyInfo pi = new PropertyInfo();   
        pi.setName("Parameter 1");
        pi.setValue(1);
        pi.setType(pi.INTEGER_CLASS);
        request.addProperty(pi);

        PropertyInfo pi2 = new PropertyInfo();  
        pi2.setName("Parameter 2");
        pi2.setValue("Any string");
        pi2.setType(pi2.STRING_CLASS);
        request.addProperty(pi2);

        SoapSerializationEnvelope envelope = new  SoapSerializationEnvelope(SoapEnvelope.VER11);
        envelope.dotNet=true;
        envelope.setOutputSoapObject(request);

        HttpTransportSE androidHttpTransport = new HttpTransportSE(URL);
        androidHttpTransport.call(SOAP_ACTION, envelope);                   
        //SoapObject result=(SoapObject)envelope.getResponse();             
        SoapPrimitive  result = (SoapPrimitive) envelope.getResponse();
        String resultData = result.toString();

        //String string1=result.getProperty(0).toString();
        //String string2=result.getProperty(1).toString();

        Log.v("WEBSERVICE","RESPONSE: "+resultData);
    } catch (Exception e) {
        e.printStackTrace();    

    }        
}

}

有谁能告诉我,如果我在这里做错了什么..另一个非常重要的问题: 谁能告诉我为什么我不能在这里使用getProperty(0)或getProperty(1)方法。我应该从webservice获得两个字符串,但我不能使用带有SoapPrimitive的getProperty(index)。 所有建议表示赞赏 谢谢

1 个答案:

答案 0 :(得分:0)

我不确定这是你需要的确切解决方案,但这对我有用,我之前遇到了同样的问题,但是需要5个参数,我只是使用SoapObject添加了3个参数,所以它给出了这种类型的错误,所以在调用此webservice之前,请确保使用 request.addProperty(“test”,“test”)添加了所有必需参数。