Question

解析XML文件时，我收到MalformedByteSequenceException。

我的应用允许外部客户提交XML文件。他们可以使用任何支持的编码，但大多数都会根据提供给他们的示例在文件顶部指定...encoding="UTF-8"...。但是有些人会使用windows-1252来编码他们的数据，这会导致非ascii字符的MalformedByteSequenceException。

我想使用XML解析器来识别文件编码并解码文件，因此我不希望有一个测试编码或将InputStream转换为Reader的初步步骤。我觉得XML解析器应该处理这一步。

即使我已经声明了ValidationEventHandler，但在MalformedByteSequenceException时也不会调用它。

有没有办法让Unmarshaller报告发生错误的文件中的位置？

这是我的Java代码：

InputStream input = ...
JAXBContext jc = JAXBContext.newInstance(MyClass.class.getPackage().getName());
Unmarshaller unmarshaller = jc.createUnmarshaller();
SchemaFactory sf = SchemaFactory.newInstance(javax.xml.XMLConstants.W3C_XML_SCHEMA_NS_URI);
Source source = new StreamSource(getClass().getResource("my.xsd").toExternalForm());
Schema schema = sf.newSchema(sources);
unmarshaller.setSchema(schema);
ValidationEventHandler handler = new MyValidationEventHandler();
unmarshaller.setEventHandler(handler);
MyClass myClass = (MyClass) unmarshaller.unmarshal(input);

以及生成的堆栈跟踪

javax.xml.bind.UnmarshalException
 - with linked exception:
[com.sun.org.apache.xerces.internal.impl.io.MalformedByteSequenceException: Invalid byte 2 of 4-byte UTF-8 sequence.]
        at com.sun.xml.internal.bind.v2.runtime.unmarshaller.UnmarshallerImpl.unmarshal0(UnmarshallerImpl.java:202)
        at com.sun.xml.internal.bind.v2.runtime.unmarshaller.UnmarshallerImpl.unmarshal(UnmarshallerImpl.java:173)
        at javax.xml.bind.helpers.AbstractUnmarshallerImpl.unmarshal(AbstractUnmarshallerImpl.java:137)
        at javax.xml.bind.helpers.AbstractUnmarshallerImpl.unmarshal(AbstractUnmarshallerImpl.java:184)
        at (my code)
Caused by: com.sun.org.apache.xerces.internal.impl.io.MalformedByteSequenceException: Invalid byte 2 of 4-byte UTF-8 sequence.
        at com.sun.org.apache.xerces.internal.impl.io.UTF8Reader.invalidByte(UTF8Reader.java:684)
        at com.sun.org.apache.xerces.internal.impl.io.UTF8Reader.read(UTF8Reader.java:470)
        at com.sun.org.apache.xerces.internal.impl.XMLEntityScanner.load(XMLEntityScanner.java:1742)
        at com.sun.org.apache.xerces.internal.impl.XMLEntityScanner.scanContent(XMLEntityScanner.java:916)
        at com.sun.org.apache.xerces.internal.impl.XMLDocumentFragmentScannerImpl$FragmentContentDriver.next(XMLDocumentFragmentScannerImpl.java:2788)
        at com.sun.org.apache.xerces.internal.impl.XMLDocumentScannerImpl.next(XMLDocumentScannerImpl.java:648)
        at com.sun.org.apache.xerces.internal.impl.XMLNSDocumentScannerImpl.next(XMLNSDocumentScannerImpl.java:140)
        at com.sun.org.apache.xerces.internal.impl.XMLDocumentFragmentScannerImpl.scanDocument(XMLDocumentFragmentScannerImpl.java:511)
        at com.sun.org.apache.xerces.internal.parsers.XML11Configuration.parse(XML11Configuration.java:808)
        at com.sun.org.apache.xerces.internal.parsers.XML11Configuration.parse(XML11Configuration.java:737)
        at com.sun.org.apache.xerces.internal.parsers.XMLParser.parse(XMLParser.java:119)
        at com.sun.org.apache.xerces.internal.parsers.AbstractSAXParser.parse(AbstractSAXParser.java:1205)
        at com.sun.org.apache.xerces.internal.jaxp.SAXParserImpl$JAXPSAXParser.parse(SAXParserImpl.java:522)
        at com.sun.xml.internal.bind.v2.runtime.unmarshaller.UnmarshallerImpl.unmarshal0(UnmarshallerImpl.java:200)
        ... 51 more

Answer 1

我没有测试，但我会

使用SAXSource（javax.xml.transform.sax.SAXSource）代替StreamSource
将我自己的org.xml.sax.ErrorHandler实现与SAXSource相关联（SAXSource.getXMLReader（）。setErrorHandler）

就像那样，我会收到SAXParseException的通知，其中存在解析错误的位置。

如何在XML解析器抛出MalformedByteSequenceException之后找到错误

1 个答案: