Question

我有一个名为 outage_name 的 ModelChoiceField 。我还有一个简单的表单，允许您从列表中选择项目。 ModelChoiceField是从MySQL DB中提取的。此查询集位于forms.py

中

outage_name = forms.ModelChoiceField(queryset = Outage.objects.filter(published = True)

models.py如下所示。

from django.db import models
from django.contrib.auth.models import User

class Outage(models.Model):
    outage_name = models.CharField(max_length=60, unique=True)
    published = models.BooleanField()
    def __unicode__(self):
        return self.outage_name

class Detail(models.Model):
    detail = models.CharField(max_length=60, unique=True)
    user = models.ForeignKey(User)
    outage = models.ForeignKey(Outage)
    def __unicode__(self):
        return self.outage

当我从列表中选择并提交表单时，我似乎无法弄清楚如何匹配列表中选择的 outage = models.ForeignKey（Outage）。到正确的 outage_name 。在我的views.py中，我可以对id进行硬编码，然后提交到数据库，一切正常。

def turnover_form(request):
    if request.user.is_authenticated():
        if request.method == 'POST':
            form = TurnoverForm(request.POST)
            if form.is_valid():         
                details = Detail.objects.get_or_create(
                    detail  = form.cleaned_data['detail'],
                    user = request.user,
                    outage = Outage.objects.get(pk=1))
            return HttpResponseRedirect('/turnover/user/')
        else:
            form = TurnoverForm()
        variables = RequestContext(request, {'form': form})
        return render_to_response('turnover_form.html', variables)
    else:
        return HttpResponseRedirect('/authorization/')

有关如何将id与所选项目进行匹配的任何建议将不胜感激。我确信我的代码不是非常pythonic，因为我还在学习。

Answer 1

outage = form.cleaned_data['outage'] # cleaned_data['outage'] is a model instance

Django将来自ModelChoiceField的ForeignKey与MySQL进行匹配

1 个答案: