Question

我正在处理的应用程序的加载网页速度非常慢。如果我运行以下代码它工作正常，但只是因为调用sleep。如果我不睡觉，那么InputStream只是一堆空格，可能是由于它调用的应用程序。这有什么非黑客方式吗？

public class PublishTool extends Thread {

  private URL publishUrl;

  private String filerLocation;

  public PublishTool() {
  }

  public PublishTool(String publishUrl, String filerLocation) throws NibException {

    try {
      this.publishUrl = new URL(publishUrl);
    } catch (MalformedURLException e) {
      throw new NibException("Publish Url :" + publishUrl + " is not valid. ");
    }

    this.filerLocation = filerLocation;

  }

  public void run() {

    File filerFile = new File(filerLocation);
    BufferedWriter writer = null;


    try {
      URLConnection conn = publishUrl.openConnection();
      BufferedReader reader = new BufferedReader(new InputStreamReader(new BufferedInputStream(conn.getInputStream())));

      writer = new BufferedWriter(new FileWriter(filerLocation));

      Thread.sleep(1000l);

      while (reader.ready()) {
        writer.write(reader.readLine() + "\n");
      }

    } catch (MalformedURLException e) {
      throw new IllegalStateException("Malformed URL for : " + publishUrl + " " + filerLocation, e);
    } catch (IOException e) {
      throw new IllegalStateException("IO Exception for  : " + publishUrl + " " + filerLocation, e);
    } catch (InterruptedException e) {
      throw new IllegalStateException("Thread was interrupted early... publishing might have failed.");
    } catch (NibException e) {
      throw new IllegalStateException("Publishing File Copy failed : " + filerLocation + ".bak" + " to " + filerLocation);
    } finally {
      try {
        writer.flush();
        writer.close();
      } catch (IOException e) {
        e.printStackTrace();
      }
    }
  }

Answer 1

不要使用reader.ready（）。只需调用readLine（）并让readLine（）阻塞，直到数据准备就绪。数据的结尾通常会用空行发出信号。

如果它有用，我的网站上有几个代码示例：reading from a URL。

Answer 2

首先，如果您发布了实际代码，将会很有帮助。

我猜这个问题是调用Reader.ready。与InputStream.available类似，如果已经有缓冲输入，则返回true。如果需要等待套接字，它将返回false。通常，您不需要ready。使用readLine，如果它返回null（对于流的结尾），则跳出循环。

Java URL连接空白输入流

2 个答案: