Question

我学会了解从URL实际链接重定向的位置。在重定向URL网站上的testinf之后，它给出了url重定向类型301。所以，我根据下面的链接进行测试，以获得真正的链接。 Get hold of redirect url with Java org.apache.http.client

代码如下所示：

HttpGet httpget = new HttpGet(filename);
HttpContext context = new BasicHttpContext(); 
DefaultHttpClient httpClient = new DefaultHttpClient();
HttpResponse response = httpClient.execute((HttpUriRequest) httpget, context); 
if (response.getStatusLine().getStatusCode() != HttpStatus.SC_OK)
    throw new IOException(response.getStatusLine().toString());
HttpUriRequest currentReq = (HttpUriRequest) context.getAttribute(ExecutionContext.HTTP_REQUEST);
HttpHost currentHost = (HttpHost)  context.getAttribute(ExecutionContext.HTTP_TARGET_HOST);
String currentUrl = currentHost.toURI() + currentReq.getURI();
System.out.println(currentUrl);

但我收到了这条消息：

AbstractHttpClient类型中的方法execute（HttpUriRequest，HttpContext）不适用于参数（HttpGet，HttpContext）

有些人会帮助我，这段代码有什么问题吗？

Answer 1

使用此httpclient依赖项，您的代码适用于我：

<dependency>
    <groupId>org.apache.httpcomponents</groupId>
    <artifactId>httpclient</artifactId>
    <version>4.1.2</version>
</dependency>

并使用这些导入：

import org.apache.http.HttpHost;
import org.apache.http.HttpResponse;
import org.apache.http.HttpStatus;
import org.apache.http.client.methods.HttpGet;
import org.apache.http.client.methods.HttpUriRequest;
import org.apache.http.impl.client.DefaultHttpClient;
import org.apache.http.protocol.BasicHttpContext;
import org.apache.http.protocol.ExecutionContext;
import org.apache.http.protocol.HttpContext;

检查您是否使用了正确的依赖项。

在Java中重定向URL类型301

1 个答案: