Question

我有一个表存储所有出站SMS短信。第二个表存储每封邮件的多个送达回执（每封邮件的送达收据在1到20之间）。

我有以下SQL：

SELECT
    messages_sent.id,
    messages_sent.user_id,
    messages_sent.api_key,
    messages_sent.to,
    messages_sent.message,
    messages_sent.sender_id,
    messages_sent.route,
    messages_sent.submission_reference,
    messages_sent.unique_submission_reference,
    messages_sent.reason_code,
    messages_sent.timestamp,
    MAX(delivery_receipts.id) AS dlr_id,
    delivery_receipts.dlr_status
FROM
    messages_sent
LEFT OUTER JOIN
    delivery_receipts
ON
    messages_sent.id = delivery_receipts.message_id
WHERE
    message_id = '466182'
GROUP BY
    messages_sent.id

消息＃466182有2个送达回执。

返回正确的dlr_id（最近的一个）但是，返回的dlr_status是第一个。 dlr_status应为5而不是2。

非常感谢任何帮助。

Answer 1

改为：

Select m.id, m.user_id, m.api_key, m.to, 
    m.message, m.sender_id, m.route, 
    m.submission_reference, 
    m.unique_submission_reference,  
    m.reason_code, m.timestamp, 
    d.id dlr_id, d.dlr_status
From messages_sent m 
   Left Join delivery_receipts d 
      On d.message_id = m.id 
         And d.dlr_id = (Select Max(dlr_id)
                         From delivery_receipts 
                         Where message_id = m.id)
Where message_id = '466182'

Answer 2

只需对您的查询稍作调整即可：

SELECT
  m.id, m.user_id, m.api_key, m.to, m.message, m.sender_id, m.route, 
  m.submission_reference, m.unique_submission_reference, m.reason_code, 
  m.timestamp, MAX(d.id) AS dlr_id, 
  (select d1.dlr_status
  from delivery_receipts d1
  where d1.id = max(d.id)) as dlr_status
FROM
  messages_sent m
LEFT OUTER JOIN
  delivery_receipts d
ON
  m.id = d.message_id
AND
  d.message_id = '466182'
GROUP BY
  m.id

请检查。

MySQL Left Outer Join，MAX（）和其他列

2 个答案: