我在xsl-fo中创建一个表，其元素数量未定义（indtr）。
我想知道是否有一种聪明的方法可以做到这一点？
这是我输入的xml文件
<pr-levels>
<prs>
<pr_nme><![CDATA[Level 1]]></pr_nme>
<nt><![CDATA[standards:]]></nt>
<b_is>
<indtr id="5684"><![CDATA[cell_1]]></indtr>
<indtr id="5684"><![CDATA[cell_2]]></indtr>
<indtr id="5684"><![CDATA[cell_3]]></indtr>
<indtr id="5684"><![CDATA[cell_4]]></indtr>
</b_is>
</prs>
<prs>
<pr_nme><![CDATA[Level 2]]></pr_nme>
<nt><![CDATA[standards:]]></nt>
<b_is>
<indtr id="5684"><![CDATA[cell_1]]></indtr>
</b_is>
</prs>
<prs>
<pr_nme><![CDATA[Level 3]]></pr_nme>
<nt><![CDATA[standards:]]></nt>
<b_is>
<indtr id="5684"><![CDATA[cell_1]]></indtr>
<indtr id="5684"><![CDATA[cell_2]]></indtr>
</b_is>
</prs>
<prs>
<pr_nme><![CDATA[Level 4]]></pr_nme>
<nt><![CDATA[standards:]]></nt>
<b_is>
<indtr id="5684"><![CDATA[cell_1]]></indtr>
<indtr id="5684"><![CDATA[cell_2]></indtr>
<indtr id="5684"><![CDATA[cell_3]]></indtr>
<indtr id="5684"><![CDATA[cell_4]></indtr>
<indtr id="5684"><![CDATA[cell_5]]></indtr>
<indtr id="5684"><![CDATA[cell_6]]></indtr>
<indtr id="5684"><![CDATA[cell_7]]></indtr>
</b_is>
</prs>
<prs>
<pr_nme><![CDATA[Level 5]]></pr_nme>
<nt><![CDATA[standards:]]></nt>
<b_is>
<indtr id="5684"><![CDATA[cell_1]]></indtr>
<indtr id="5684"><![CDATA[cell_2]]></indtr>
<indtr id="5684"><![CDATA[cell_3]]></indtr>
<indtr id="5684"><![CDATA[cell_4]]></indtr>
<indtr id="5684"><![CDATA[cell_5]]></indtr>
<indtr id="5684"><![CDATA[cell_6]]></indtr>
<indtr id="5684"><![CDATA[cell_7]]></indtr>
<indtr id="5684"><![CDATA[cell_8]]></indtr>
<indtr id="5684"><![CDATA[cell_9]]></indtr>
<indtr id="5684"><![CDATA[cell_10]]></indtr>
<indtr id="5684"><![CDATA[cell_11]]></indtr>
<indtr id="5684"><![CDATA[cell_12]]></indtr>
<indtr id="5684"><![CDATA[cell_13]]></indtr>
<indtr id="5684"><![CDATA[cell_14]]></indtr>
<indtr id="5684"><![CDATA[cell_15]]></indtr>
<indtr id="5684"><![CDATA[cell_16]]></indtr>
<indtr id="5684"><![CDATA[cell_17]]></indtr>
<indtr id="5684"><![CDATA[cell_18]]></indtr>
<indtr id="5684"><![CDATA[cell_19]]></indtr>
</b_is>
</prs>
</pr-levels>
这是我的XSLT模板，它生成XSL-FO表：
<xsl:template match="pr-levels">
<fo:table xsl:use-attribute-sets="table_p" break-after="page" force-page-count="no-force">
<fo:table-column column-number="1" xsl:use-attribute-sets="table_col_p"/>
<fo:table-column column-number="2" xsl:use-attribute-sets="table_col_p"/>
<fo:table-column column-number="3" xsl:use-attribute-sets="table_col_p"/>
<fo:table-column column-number="4" xsl:use-attribute-sets="table_col_p"/>
<fo:table-column column-number="5" xsl:use-attribute-sets="table_col_p"/>
<fo:table-header xsl:use-attribute-sets="table_header">
<xsl:for-each select="prs/pr_nme">
<fo:table-cell>
<fo:block>
<xsl:apply-templates/>
</fo:block>
</fo:table-cell>
</xsl:for-each>
</fo:table-header>
<fo:table-body >
<fo:table-row>
<xsl:for-each select="prs/nt">
<fo:table-cell>
<fo:block xsl:use-attribute-sets="nt" >
<xsl:apply-templates/>
</fo:block>
</fo:table-cell>
</xsl:for-each>
</fo:table-row>
<fo:table-row>
<xsl:for-each select="prs/b_is">
<fo:table-cell padding="1pt">
<fo:block>
<xsl:value-of select="indtr[1]"/>
</fo:block>
</fo:table-cell>
</xsl:for-each>
</fo:table-row>
<fo:table-row>
<xsl:for-each select="prs/b_is">
<fo:table-cell padding="1pt">
<fo:block>
<xsl:value-of select="indtr[2]"/>
</fo:block>
</fo:table-cell>
</xsl:for-each>
</fo:table-row>
<fo:table-row>
<xsl:for-each select="prs/b_is">
<fo:table-cell padding="1pt">
<fo:block>
<xsl:value-of select="indtr[3]"/>
</fo:block>
</fo:table-cell>
</xsl:for-each>
</fo:table-row>
<fo:table-row>
<xsl:for-each select="prs/b_is">
<fo:table-cell padding="1pt">
<fo:block>
<xsl:value-of select="indtr[4]"/>
</fo:block>
</fo:table-cell>
</xsl:for-each>
</fo:table-row>
<fo:table-row>
<xsl:for-each select="prs/b_is">
<fo:table-cell padding="1pt">
<fo:block>
<xsl:value-of select="indtr[5]"/>
</fo:block>
</fo:table-cell>
</xsl:for-each>
</fo:table-row>
</fo:table-body>
</fo:table>
</xsl:template>
<indtr>中可能有NULL，1,69或任意数量的<b_is>，但现在我只是硬编码。我的问题是如何动态计算数量indtrs并在我的表中添加行。可能是xsl中的for循环？
________________________________________________________
| level 1 | level 2 | level 3 | level 4 | level 5 |
--------------------------------------------------------
|standards:|standards:|standards:|standards:|standards:|
--------------------------------------------------------
| cell 1 | cell 1 | cell 1 | cell 1 | cell 1 |
--------------------------------------------------------
| cell 2 | cell 2 | cell 2 | cell 2 | cell 2 |
--------------------------------------------------------
| | cell 3 | cell 3 | cell 3 | cell 3 |
--------------------------------------------------------
| | cell 4 | | | cell 4 |
--------------------------------------------------------
| | | | | cell 5 |
--------------------------------------------------------
| | | | | cell 6 |
--------------------------------------------------------
答案 0 :(得分：0)
仅仅因为这是一个有趣的问题......
将多个硬编码的fo:table-row替换为：
<xsl:variable name="pr-levels" select="." />
<xsl:for-each
select="1 to max(for $prs in prs
return count($prs/b_is/indtr))">
<xsl:variable name="row" select="." as="xs:integer" />
<fo:table-row>
<xsl:for-each select="$pr-levels/prs">
<fo:table-cell padding="1pt">
<fo:block>
<xsl:value-of select="b_is/indtr[$row]"/>
</fo:block>
</fo:table-cell>
</xsl:for-each>
</fo:table-row>
</xsl:for-each>