Question

他们有一个asp.net（vb）Web应用程序来存储加班（OT）记录。

在SQL服务器中，OT表喜欢这样，例如：

ot_key | From Time        | To Time          | total_min
12     | 2011-09-22 10:00 | 2011-09-22 13:00 | 180
13     | 2011-09-24 14:00 | 2011-09-24 15:00 | 60
14     | 2011-09-23 12:00 | 2011-09-23 14:30 | 150
15     | 2011-09-24 18:00 | 2011-09-24 19:30 | 90

由于用户将输入以前的日期OT记录，因此db中的记录将不会按顺序排列。记录＃14的日期在记录＃13之前。

如果用户想知道过去2小时内哪些OT记录，系统应检索记录＃15 （90分钟）＆amp; ＃13 （30分钟），因为它们涵盖最后2个小时。

如何编写SQL语句来检索记录？感谢

乔

Answer 1

如果我理解正确的话，你需要做的就是这个（但是你提出问题的方式很奇怪，所以我不确定你在寻找什么。

 select * from OT where total_min <=
 [number of hours expressed in minutes]

Answer 2

CREATE TABLE OT (
    [ot_key] INT,
    [From Time] DATETIME,
    [To Time] DATETIME,
    [total_min] INT
)

INSERT  OT
VALUES  (12,'2011-09-22 10:00', '2011-09-22 13:00', 180),
        (13, '2011-09-24 14:00', '2011-09-24 15:00', 60),
        (14, '2011-09-23 12:00', '2011-09-23 14:30', 150),
        (15, '2011-09-24 18:00', '2011-09-24 19:30', 90)

查询：

DECLARE @CoverTime INT = 120

;WITH cteOTRN AS (
    SELECT ROW_NUMBER() OVER (ORDER BY [To Time] DESC) AS [ROW_NUMBER], *
    FROM OT
)
, cteOTRT AS (
    SELECT *
    FROM cteOTRN ot
    CROSS APPLY (
        SELECT  SUM([total_min]) AS [RunningTotal]
        FROM cteOTRN
        WHERE [ROW_NUMBER] <= ot.[ROW_NUMBER]
    ) rt
)
SELECT *, [total_min] AS [CoverTime]
FROM cteOTRT ot
WHERE [RunningTotal] <= @CoverTime
UNION 
SELECT TOP 1 *, [RunningTotal] - @CoverTime
FROM cteOTRT ot
WHERE NOT ([RunningTotal] <= @CoverTime)
AND NOT EXISTS (
    SELECT *
    FROM cteOTRT ot
    WHERE [RunningTotal] = @CoverTime
)
ORDER BY [To Time] DESC

另见Calculate a Running Total in SQL Server

Answer 3

做一个

select * from OT where datediff(hour,ToTime,getdate()) < 2

将为您提供当前时间与全天时间之差小于2小时的帖子。

如何在SQL Server中检索最近几个小时的记录

3 个答案: