Question

您好我需要将节点从一个XML复制到另一个XML：

String _sPathOfrObj = "/response/grp/ofr/obj";
String _sPathHotelData = "/main/hotelData";
String _sPathStatus = "/main/status";
xpath.reset();
NodeList status = (NodeList) xpath.evaluate( _sPathStatus, details, XPathConstants.NODESET );
if(status.item( 0 ).getTextContent().equalsIgnoreCase( "ok" ))
{
    NodeList nodes3 = (NodeList) xpath.evaluate( _sPathOfrObj, result, XPathConstants.NODESET );
    NodeList nodes4 = (NodeList) xpath.evaluate( _sPathHotelData, details, XPathConstants.NODESET);
    minimum = Math.min( nodes3.getLength(), nodes4.getLength() );

    Log.i(CLASS_NAME, "obj="+nodes3.getLength());
    Log.i(CLASS_NAME, "hdat="+nodes4.getLength());

    for (i = 0; i < minimum; i++)
    {
        try
        {
            nodes3.item( i ).appendChild( nodes4.item( i ) );
        }
        catch(DOMException dome)
        {
            dome.printStackTrace();
            Log.e(CLASS_NAME, dome.code+"" );
        }
    }
}

但它会生成错误，DOMException为WRONG_DOCUMENT_ERR，或者当我执行nodes4.item( i ).deepClone(true or false)时，它将抛出DOMException NAMESPACE_ERR

有办法吗？

非常感谢

Answer 1

我已经设法让它工作，它是我的解决方案的混合物，克服了深度抛出NAMESPACE_ERR和link中提出的解决方案。

基本上我无法在没有错误的情况下制作给定节点的副本，因此我将XML扁平化为字符串并将字符串转换为新节点并使用adoptNode我有我的解决方案:)

我确实知道这是一个黑客的地狱，但它适用于我紧迫的截止日期：）

转换为字符串是通过使用Transformer类完成的，如下所示：

private static final String CLASS_NAME = "SendQueryTask";
//...
import java.io.StringWriter;

import javax.xml.transform.OutputKeys;
import javax.xml.transform.Transformer;
import javax.xml.transform.TransformerConfigurationException;
import javax.xml.transform.TransformerException;
import javax.xml.transform.TransformerFactory;
import javax.xml.transform.TransformerFactoryConfigurationError;
import javax.xml.transform.dom.DOMSource;
import javax.xml.transform.stream.StreamResult;
//...
private String transformXmlToString(Node node)
{
    Transformer transformer = null;
    try
    {
        transformer = TransformerFactory.newInstance().newTransformer();
    }
    catch (TransformerConfigurationException e)
    {
        // TODO Auto-generated catch block
        e.printStackTrace();
    }
    catch (TransformerFactoryConfigurationError e)
    {
        // TODO Auto-generated catch block
        e.printStackTrace();
    }
    if ( transformer != null )
    {
        transformer.setOutputProperty( OutputKeys.INDENT, "yes" );

        // initialize StreamResult with File object to save to file
        StreamResult result = new StreamResult( new StringWriter() );
        DOMSource source = new DOMSource( node );

        try
        {
            transformer.transform( source, result );
        }
        catch (TransformerException e)
        {
            // TODO Auto-generated catch block
            e.printStackTrace();
        }

        String xmlString = result.getWriter().toString();
        Log.i( CLASS_NAME, "flattened=" + (xmlString) );

        return xmlString;
    }       
    return null;
}

并将其转换回Node

import java.io.ByteArrayInputStream;
import java.io.IOException;
import java.io.InputStream;
import org.apache.http.protocol.HTTP;
import java.io.UnsupportedEncodingException;

private Node dumbNodeCopy(Node item)
{
    String xmlString = transformXmlToString( item );

    if ( xmlString != null )
    {
        InputStream is = null;
        try
        {
            is = new ByteArrayInputStream( xmlString.getBytes( HTTP.UTF_8 ) );
        }
        catch (UnsupportedEncodingException e)
        {
            e.printStackTrace();
        }

        if ( is != null )
        {
            Document doc = null;
            dbf = DocumentBuilderFactory.newInstance();
            try
            {
                db = dbf.newDocumentBuilder();
                doc = db.parse( is );
                doc.getDocumentElement().normalize();

            }
            catch (ParserConfigurationException e)
            {
                e.printStackTrace();
            }
            catch (SAXException e)
            {
                e.printStackTrace();
            }
            catch (IOException e)
            {
                e.printStackTrace();
            }

            if ( doc != null ) return doc.getFirstChild();
        }
        return null;
    }
    return null;

最后复制

NodeList nodes3 = (NodeList) xpath.evaluate( _sPathOfrObj, result,
        XPathConstants.NODESET );
NodeList nodes4 = (NodeList) xpath.evaluate( _sPathHotelData, details,
        XPathConstants.NODESET );
minimum = Math.min( nodes3.getLength(), nodes4.getLength() );

Log.i( CLASS_NAME, "obj=" + nodes3.getLength() );
Log.i( CLASS_NAME, "hdat=" + nodes4.getLength() );

for (i = 0; i < minimum; i++)
{
    try
    {
        Node copy = dumbNodeCopy( nodes4.item( i ) );
        if ( copy != null )
        {
            // nodes3.item( i ).appendChild( copy );
            nodes3.item( i ).appendChild(
                    nodes3.item( i ).getOwnerDocument().adoptNode( copy ) );
        }
        else
            Log.e( CLASS_NAME, "Copy of nodes4#" + i + ", failed." );
    }
    catch (DOMException dome)
    {
        dome.printStackTrace();
        Log.e( CLASS_NAME, dome.code + "" );
    }
}

顺便说一句。不要嘲笑代码:-)我知道它看起来很糟糕但我的必要ATM是为了满足最后期限，如果有人会提出简洁的解决方案，我会很乐意坚持：）

android XPath，将节点从一个文档复制到另一个文档

1 个答案: