Question

我有以下类实现IXmlSerializable：

[System.Diagnostics.DebuggerStepThroughAttribute()]
[System.CodeDom.Compiler.GeneratedCodeAttribute("System.Runtime.Serialization", "4.0.0.0")]
[System.Xml.Serialization.XmlSchemaProviderAttribute("ExportSchema")]
[System.Xml.Serialization.XmlRootAttribute(IsNullable = false)]
public partial class ExceptionReport : object, System.Xml.Serialization.IXmlSerializable
{
    private System.Xml.XmlNode[] nodesField;

    private static System.Xml.XmlQualifiedName typeName = new System.Xml.XmlQualifiedName("ExceptionReport", "http://www.opengis.net/ows");

    public System.Xml.XmlNode[] Nodes
    {
        get
        {
            return this.nodesField;
        }
        set
        {
            this.nodesField = value;
        }
    }

    public void ReadXml(System.Xml.XmlReader reader)
    {
        this.nodesField = System.Runtime.Serialization.XmlSerializableServices.ReadNodes(reader);
    }

    public void WriteXml(System.Xml.XmlWriter writer)
    {
        System.Runtime.Serialization.XmlSerializableServices.WriteNodes(writer, this.Nodes);
    }

    public System.Xml.Schema.XmlSchema GetSchema()
    {
        return null;
    }

    public static System.Xml.XmlQualifiedName ExportSchema(System.Xml.Schema.XmlSchemaSet schemas)
    {
        System.Runtime.Serialization.XmlSerializableServices.AddDefaultSchema(schemas, typeName);
        return typeName;
    }
}

当我抛出这样的错误时：

throw new FaultException<ExceptionReport>(exceptions.GetExceptionReport(), new FaultReason("A server exception was encountered."), new FaultCode("Receiver"));

我在soap fault详细信息中获得了以下XML：

...
<detail>
    <ExceptionReport xmlns="http://www.opengis.net/ows">
        <ows:Exception exceptionCode="NoApplicableCode" locator="somewhere" xmlns:ows="http://www.opengis.net/ows">
            <ows:ExceptionText>mymessage</ows:ExceptionText>
        </ows:Exception>
    </ExceptionReport>
</detail>
...

但我真正想要的是根据ExceptionReport元素的“ows”前缀：

...
<detail>
    <ows:ExceptionReport xmlns:ows="http://www.opengis.net/ows">
        <ows:Exception exceptionCode="NoApplicableCode" locator="somewhere" xmlns:ows="http://www.opengis.net/ows">
            <ows:ExceptionText>mymessage</ows:ExceptionText>
        </ows:Exception>
    </ows:ExceptionReport>
</detail>
...

如何添加该前缀？

Answer 1

如何将属性添加到ExceptionReport并使用XmlNamespaceDeclarationsAttribute进行装饰，并在Namespace类上设置XmlRoot属性的ExceptionReport属性，如下所示：

...
[XmlRoot(IsNullable = false, Namespace = "http://www.opengis.net/ows")]
public partial class ExceptionReport
{
    [XmlNamespaceDeclarations()]
    public XmlSerializerNamespaces xmlns
    {
       get
       {
           XmlSerializerNamespaces xmlns = new XmlSerializerNamespaces();
           xmlns.Add("ows", "http://www.opengis.net/ows");
           return xmlns;
       }
       set
       { 
       }
   }

   ...
}

当然，您可以在构造函数中或任何您想要的位置填充名称空间，关键是要有一个返回正确的XmlSerializerNamespaces实例的属性。

为序列化的XML元素添加前缀

1 个答案: