我有问题:
Thread :: tdlen:{Null} {}中长度不等的对象无法组合。 >>
这似乎发生在while测试中,因为我在比较数字时没有任何意义......?
该程序是一个解决0-1背包动态编程问题的程序,虽然我使用循环,而不是递归。
我已经放了一些打印输出,我只能认为问题出在while循环中并且没有意义。
(* 0-1 Knapsack problem
item = {value, weight}
Constraint is maxweight. Objective is to max value.
Input on the form:
Matrix[{value,weight},
{value,weight},
...
]
*)
lookup[x_, y_, m_] := m[[x, y]];
generateTable[items_, maxweight_] := {
nbrofitems = Dimensions[items][[1]];
keep = values = Table[0, {j, 0, nbrofitems}, {i, 1, maxweight}];
For[j = 2, j <= nbrofitems + 1, j++,
itemweight = items[[j - 1, 2]];
itemvalue = items[[j - 1, 1]];
For[i = 1, i <= maxweight, i++,
{
x = lookup[j - 1, i, values];
diff = i - itemweight;
If[diff > 0, y = lookup[j - 1, diff, values], y = 0];
If[itemweight <= i ,
{If[x < itemvalue + y,
{values[[j, i]] = itemvalue + y; keep[[j, i]] = 1;},
{values[[j, i]] = x; keep[[j, i]] = 0;}]
},
y(*y eller x?*)]
}
]
];
{values, keep}
}
pickItems[keep_, items_, maxweight_] :=
{
(*w=remaining weight in knapsack*)
(*i=current item*)
w = maxweight;
knapsack = {};
nbrofitems = Dimensions[items][[1]];
i = nbrofitems + 1;
x = 0;
While[i > 0 && x < 10,
{
Print["lopp round starting"];
x++;
Print["i"];
Print[i];
Print["w"];
Print[w];
Print["keep[i,w]"];
Print[keep[[i, w]]];
If[keep[[i, w]] == 1,
{Append[knapsack, i];
Print["tjolahej"];
w -= items[[i - 1, 2]];
i -= 1;
Print["tjolahopp"];
},
i -= 1;
];
Print[i];
Print["loop round done"];
}
knapsack;
]
}
Clear[keep, v, a, b, c]
maxweight = 5;
nbrofitems = 3;
a = {5, 3};
b = {3, 2};
c = {4, 1};
items = {a, b, c};
MatrixForm[items]
results = generateTable[items, 5];
keep = results[[1]][[2]];
Print["keep:"];
MatrixForm[keep]
Print["------"];
results2 = pickItems[keep, items, 5];
MatrixForm[results2]
答案 0 :(得分:1)
这不是对所询问的具体问题的真正答案,而是对发生此错误时的一般情况的一些提示。简短的回答是,这是将不等长度列表传递给某些Listable
函数,用户定义或内置函数的标志。
Mathematica的许多内置函数都是Listable
(具有Listable
属性)。这基本上意味着,给定列表代替一些或所有参数,Mathematica会自动将函数与它们进行线程化。真正发生的是内部调用Thread
(或者至少,它出现)。
In[15]:=
ClearAll[f];
SetAttributes[f,Listable];
f[{1,2},{3,4,5}]
During evaluation of In[15]:= Thread::tdlen: Objects of unequal length in
f[{1,2},{3,4,5}] cannot be combined. >>
Out[17]= f[{1,2},{3,4,5}]
明确使用Thread
可以获得相同的行为:
In[19]:=
ClearAll[ff];
Thread[ff[{1,2},{3,4,5}]]
During evaluation of In[19]:= Thread::tdlen: Objects of unequal length in
ff[{1,2},{3,4,5}] cannot be combined. >>
Out[20]= ff[{1,2},{3,4,5}]
在Listable
函数的情况下,这有点隐藏了。一些典型示例包括{1, 2} + {3, 4, 5}
或{1, 2}^{3, 4, 5}
等内容。我更详细地讨论了这个问题here。
答案 1 :(得分:0)
试试这个版本:
pickItems[keep_, items_, maxweight_] := Module[{},
{(*w=remaining weight in knapsack*)(*i=current item*)w = maxweight;
knapsack = {};
nbrofitems = Dimensions[items][[1]];
i = nbrofitems + 1;
x = 0;
While[i > 0 && x < 10,
{
Print["lopp round starting"];
x++;
Print["i"];
Print[i];
Print["w"];
Print[w];
Print["keep[i,w]"];
Print[keep[[i, w]]];
If[keep[[i, w]] == 1,
{
Append[knapsack, i];
Print["tjolahej"];
w -= items[[i - 1, 2]];
i -= 1;
Print["tjolahopp"];
},
i -= 1;
];
Print[i];
Print["loop round done"]
};
knapsack
]
}
]
现在没有错误,但我不知道它到底做了什么:)